Edexcel FP2 — Question 4 9 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Marks9
PaperDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeProving standard summation formulae
DifficultyStandard +0.3 This is a guided method-of-differences question with explicit scaffolding through parts (a) and (b). While it requires understanding telescoping series and algebraic manipulation, the structure heavily directs students through each step, making it easier than an average A-level question that requires independent problem-solving or novel insight.
Spec4.06a Summation formulae: sum of r, r^2, r^34.06b Method of differences: telescoping series

Given that $$(2r + 1)^3 = Ar^3 + Br^2 + Cr + 1,$$
  1. find the values of the constants \(A\), \(B\) and \(C\). [2]
  2. Show that $$(2r + 1)^3 - (2r - 1)^3 = 24r^2 + 2.$$ [2]
  3. Using the result in part (b) and the method of differences, show that $$\sum_{r=1}^n r^2 = \frac{1}{6}n(n + 1)(2n + 1).$$ [5]

Given that
$$(2r + 1)^3 = Ar^3 + Br^2 + Cr + 1,$$

\begin{enumerate}[label=(\alph*)]
\item find the values of the constants $A$, $B$ and $C$. [2]
\item Show that
$$(2r + 1)^3 - (2r - 1)^3 = 24r^2 + 2.$$ [2]
\item Using the result in part (b) and the method of differences, show that
$$\sum_{r=1}^n r^2 = \frac{1}{6}n(n + 1)(2n + 1).$$ [5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP2  Q4 [9]}}