CAIE M2 2017 June — Question 1 4 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2017
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeVelocity direction at specific time/point
DifficultyStandard +0.3 This is a straightforward projectiles question requiring resolution of velocity components and application of standard kinematic equations. Students must find when the velocity angle equals -40°, which involves setting up tan(40°) = |v_y|/v_x and solving for t. While it requires careful angle work and sign conventions, it's a standard M2 exercise with no novel insight needed—slightly easier than average due to being a single-part calculation.
Spec3.02i Projectile motion: constant acceleration model

A particle is projected with speed \(20 \text{ ms}^{-1}\) at an angle of \(60°\) above the horizontal. Calculate the time after projection when the particle is descending at an angle of \(40°\) below the horizontal. [4]

Question 1:
AnswerMarks Guidance
1tan40 = v / 20cos60 M1
v = 10tan40 ( = 8.3909...)A1
–10tan40 = 20sin60 – gtM1 Uses v = u + at vertically
t = 1.27 sA1
Total:4
Question 1:
1 | tan40 = v / 20cos60 | M1
v = 10tan40 ( = 8.3909...) | A1
–10tan40 = 20sin60 – gt | M1 | Uses v = u + at vertically
t = 1.27 s | A1
Total: | 4
A particle is projected with speed $20 \text{ ms}^{-1}$ at an angle of $60°$ above the horizontal. Calculate the time after projection when the particle is descending at an angle of $40°$ below the horizontal. [4]

\hfill \mbox{\textit{CAIE M2 2017 Q1 [4]}}