A particle is projected from a point \(O\) on horizontal ground. The initial components of the velocity of the particle are \(10 \text{ ms}^{-1}\) horizontally and \(15 \text{ ms}^{-1}\) vertically. At time \(t\) s after projection, the horizontal and vertically upwards displacements of the particle from \(O\) are \(x\) m and \(y\) m respectively.
- Express \(x\) and \(y\) in terms of \(t\), and hence find the equation of the trajectory of the particle. [4]
- Show that \(d\) is less than \(30\). [2]
- Find the value of \(x\) when the particle is \(14\) m below the level of \(O\). [2]
The horizontal ground is at the top of a vertical cliff. The point \(O\) is at a distance \(d\) m from the edge of the cliff. The particle is projected towards the edge of the cliff and does not strike the ground before it passes over the edge of the cliff.