CAIE FP2 2017 June — Question 11 24 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2017
SessionJune
Marks24
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear regression
TypeMinimize sum of squared residuals
DifficultyModerate -0.5 This is a standard linear regression question from Further Maths statistics requiring calculation of regression coefficients and related statistics using given summary data. While it involves multiple steps and careful arithmetic, it follows a completely routine procedure with no conceptual challenges or novel problem-solving required. The calculations are straightforward applications of standard formulas (Sxx, Syy, Sxy, regression line equation). This is easier than average A-level difficulty because it's purely procedural with all necessary summary statistics provided.
Spec6.02i Conservation of energy: mechanical energy principle6.04d Integration: for centre of mass of laminas/solids6.05a Angular velocity: definitions

Answer only one of the following two alternatives. EITHER \includegraphics{figure_11a} The diagram shows a uniform thin rod \(AB\) of length \(3a\) and mass \(8m\). The end \(A\) is rigidly attached to the surface of a sphere with centre \(O\) and radius \(a\). The rod is perpendicular to the surface of the sphere. The sphere consists of two parts: an inner uniform solid sphere of mass \(m\) and radius \(a\) surrounded by a thin uniform spherical shell of mass \(m\) and also of radius \(a\). The horizontal axis \(l\) is perpendicular to the rod and passes through the point \(C\) on the rod where \(AC = a\).
  1. Show that the moment of inertia of the object, consisting of rod, shell and inner sphere, about the axis \(l\) is \(\frac{289}{15}ma^2\). [6]
The object is free to rotate about the axis \(l\). The object is held so that \(CA\) makes an angle \(\alpha\) with the downward vertical and is released from rest.
  1. Given that \(\cos \alpha = \frac{1}{6}\), find the greatest speed achieved by the centre of the sphere in the subsequent motion. [6]
OR The times taken to run \(200\) metres at the beginning of the year and at the end of the year are recorded for each member of a large athletics club. The time taken, in seconds, at the beginning of the year is denoted by \(x\) and the time taken, in seconds, at the end of the year is denoted by \(y\). For a random sample of \(8\) members, the results are shown in the following table.
MemberABCDEFGH
\(x\)24.223.822.825.124.524.023.822.8
\(y\)23.923.622.824.524.223.523.622.7
\([\Sigma x = 191, \quad \Sigma x^2 = 4564.46, \quad \Sigma y = 188.8, \quad \Sigma y^2 = 4458.4, \quad \Sigma xy = 4510.99.]\)
  1. Find, showing all necessary working, the equation of the regression line of \(y\) on \(x\). [4]
The athletics coach believes that, on average, the time taken by an athlete to run \(200\) metres decreases between the beginning and the end of the year by more than \(0.2\) seconds.
  1. Stating suitable hypotheses and assuming a normal distribution, test the coach's belief at the \(10\%\) significance level. [8]

Question 11:

AnswerMarks
11(a)(i)I = ⅓ 8m (3a/2)2 + 8m (a/2)2
AB
AnswerMarks Guidance
or 8m (3a)2 /12 + 8m (a/2)2 [= 8 ma2]M1 A1 Find or state MI of rod AB about axis l
I = ⅔ ma2 + m (2a)2 [= (14/3) ma2]
AnswerMarks Guidance
shellM1 Find MI of shell about axis l
I = (2/5) (3m/2)a2 + (3m/2) (2a)2 [= (33/5) ma2]
AnswerMarks Guidance
sphereM1 A1 Find MI of sphere about axis l
I = (8 + 14/3 + 33/5) ma2 = (289/15) ma2 AGA1 Verify MI of object about axis l
Total:6

AnswerMarks Guidance
11(a)(ii)½ I ω2 = (5mg/2) 2a (1 – cos α ) – 8mg (a/2) (1 – cos α )
or ((21/2)mg × 2a/21) (1 – cos α)M1 A1 Find ω2 or angular speed ω when CA vertical by
energy
AnswerMarks
= mga (1 – cos α ) = 5mga/6A1
ω2 = 25g/289a or 0⋅0865 g/a
AnswerMarks
or ω = (5/17) √(g/a) or 0⋅294 √(g/a)A1
v = 2aω = 2a √(25g/289a)
max
AnswerMarks Guidance
= √(100ag/289) or (10/17)√(ag)M1 Find maximum speed v of O from rω
max
AnswerMarks Guidance
or 0⋅588√(ag) or 1⋅86√a (AEF)A1 (A1 requires some simplification)
Total:6

AnswerMarks
11(b)(i)e.g.
S = 4510⋅99 – 191 × 188⋅8/8 = 3⋅39 or 0⋅424
xy
S = 4564⋅46 – 1912/8 = 4⋅335 or 0⋅542
xx
b = S / S = 3⋅39/4⋅335 = 0⋅782
AnswerMarks Guidance
xy xxM1 A1 Find reqd. values
(y – 188⋅8/8) = b (x – 191/8)
AnswerMarks Guidance
(y – 23⋅6) = 0⋅782 (x – 23⋅875), y = 0⋅782x + 4⋅93M1 A1 Find gradient b in y –y = b (x –x)
and hence eqn. of regression line (may be implied
by writing y = a + bx and finding a, b)
AnswerMarks Guidance
Total:4
QuestionAnswer Marks

AnswerMarks Guidance
11(b)(ii)H : µ – µ = 0⋅2, H : µ – µ > 0⋅2 (AEF)
0 x y 1 x yB1 State both hypotheses (B0 forx … )
d: 0⋅3 0⋅2 0 0⋅6 0⋅3 0⋅5 0⋅2 0⋅1
AnswerMarks Guidance
iM1 Consider differences d, e.g. x – y
i i i
AnswerMarks Guidance
d = 2⋅2 / 8 = 0⋅275B1 Find sample mean
s2 = (0⋅88 – 2⋅22/8) / 7M1 Estimate population variance
(allow biased here: [11/320 or 0⋅0344 or 0⋅1852 ])
[ = 11/280 or 0⋅0393 or 0⋅1982]
t = 1⋅41[5]
AnswerMarks Guidance
7, 0.9B1 State or use correct tabular t-value
t = (d – 0⋅2) / (s/√8) = 1⋅07M1 A1 Find value of t
(or compare d – 0⋅2 = 0⋅075 with t s/√8 = 0⋅099)
7, 0.9
[Accept H :] No evidence for coach’s belief (AEF)
AnswerMarks Guidance
0B1 FT Consistent conclusion (FT on both t-values)
SR Wrong (hypothesis) test can earn only
B1 for hypotheses
B1FT for conclusion (max 2/8)
AnswerMarks
Total:8
Question 11:
--- 11(a)(i) ---
11(a)(i) | I = ⅓ 8m (3a/2)2 + 8m (a/2)2
AB
or 8m (3a)2 /12 + 8m (a/2)2 [= 8 ma2] | M1 A1 | Find or state MI of rod AB about axis l
I = ⅔ ma2 + m (2a)2 [= (14/3) ma2]
shell | M1 | Find MI of shell about axis l
I = (2/5) (3m/2)a2 + (3m/2) (2a)2 [= (33/5) ma2]
sphere | M1 A1 | Find MI of sphere about axis l
I = (8 + 14/3 + 33/5) ma2 = (289/15) ma2 AG | A1 | Verify MI of object about axis l
Total: | 6
--- 11(a)(ii) ---
11(a)(ii) | ½ I ω2 = (5mg/2) 2a (1 – cos α ) – 8mg (a/2) (1 – cos α )
or ((21/2)mg × 2a/21) (1 – cos α) | M1 A1 | Find ω2 or angular speed ω when CA vertical by
energy
= mga (1 – cos α ) = 5mga/6 | A1
ω2 = 25g/289a or 0⋅0865 g/a
or ω = (5/17) √(g/a) or 0⋅294 √(g/a) | A1
v = 2aω = 2a √(25g/289a)
max
= √(100ag/289) or (10/17)√(ag) | M1 | Find maximum speed v of O from rω
max
or 0⋅588√(ag) or 1⋅86√a (AEF) | A1 | (A1 requires some simplification)
Total: | 6
--- 11(b)(i) ---
11(b)(i) | e.g.
S = 4510⋅99 – 191 × 188⋅8/8 = 3⋅39 or 0⋅424
xy
S = 4564⋅46 – 1912/8 = 4⋅335 or 0⋅542
xx
b = S / S = 3⋅39/4⋅335 = 0⋅782
xy xx | M1 A1 | Find reqd. values
(y – 188⋅8/8) = b (x – 191/8)
(y – 23⋅6) = 0⋅782 (x – 23⋅875), y = 0⋅782x + 4⋅93 | M1 A1 | Find gradient b in y –y = b (x –x)
and hence eqn. of regression line (may be implied
by writing y = a + bx and finding a, b)
Total: | 4
Question | Answer | Marks | Guidance
--- 11(b)(ii) ---
11(b)(ii) | H : µ – µ = 0⋅2, H : µ – µ > 0⋅2 (AEF)
0 x y 1 x y | B1 | State both hypotheses (B0 forx … )
d: 0⋅3 0⋅2 0 0⋅6 0⋅3 0⋅5 0⋅2 0⋅1
i | M1 | Consider differences d, e.g. x – y
i i i
d = 2⋅2 / 8 = 0⋅275 | B1 | Find sample mean
s2 = (0⋅88 – 2⋅22/8) / 7 | M1 | Estimate population variance
(allow biased here: [11/320 or 0⋅0344 or 0⋅1852 ])
[ = 11/280 or 0⋅0393 or 0⋅1982]
t = 1⋅41[5]
7, 0.9 | B1 | State or use correct tabular t-value
t = (d – 0⋅2) / (s/√8) = 1⋅07 | M1 A1 | Find value of t
(or compare d – 0⋅2 = 0⋅075 with t s/√8 = 0⋅099)
7, 0.9
[Accept H :] No evidence for coach’s belief (AEF)
0 | B1 FT | Consistent conclusion (FT on both t-values)
SR Wrong (hypothesis) test can earn only
B1 for hypotheses
B1FT for conclusion (max 2/8)
Total: | 8
Answer only one of the following two alternatives.

\textbf{EITHER}

\includegraphics{figure_11a}

The diagram shows a uniform thin rod $AB$ of length $3a$ and mass $8m$. The end $A$ is rigidly attached to the surface of a sphere with centre $O$ and radius $a$. The rod is perpendicular to the surface of the sphere. The sphere consists of two parts: an inner uniform solid sphere of mass $m$ and radius $a$ surrounded by a thin uniform spherical shell of mass $m$ and also of radius $a$. The horizontal axis $l$ is perpendicular to the rod and passes through the point $C$ on the rod where $AC = a$.

\begin{enumerate}[label=(\roman*)]
\item Show that the moment of inertia of the object, consisting of rod, shell and inner sphere, about the axis $l$ is $\frac{289}{15}ma^2$. [6]
\end{enumerate}

The object is free to rotate about the axis $l$. The object is held so that $CA$ makes an angle $\alpha$ with the downward vertical and is released from rest.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Given that $\cos \alpha = \frac{1}{6}$, find the greatest speed achieved by the centre of the sphere in the subsequent motion. [6]
\end{enumerate}

\textbf{OR}

The times taken to run $200$ metres at the beginning of the year and at the end of the year are recorded for each member of a large athletics club. The time taken, in seconds, at the beginning of the year is denoted by $x$ and the time taken, in seconds, at the end of the year is denoted by $y$. For a random sample of $8$ members, the results are shown in the following table.

\begin{tabular}{|c|c|c|c|c|c|c|c|c|}
\hline
Member & A & B & C & D & E & F & G & H \\
\hline
$x$ & 24.2 & 23.8 & 22.8 & 25.1 & 24.5 & 24.0 & 23.8 & 22.8 \\
\hline
$y$ & 23.9 & 23.6 & 22.8 & 24.5 & 24.2 & 23.5 & 23.6 & 22.7 \\
\hline
\end{tabular}

$[\Sigma x = 191, \quad \Sigma x^2 = 4564.46, \quad \Sigma y = 188.8, \quad \Sigma y^2 = 4458.4, \quad \Sigma xy = 4510.99.]$

\begin{enumerate}[label=(\roman*)]
\item Find, showing all necessary working, the equation of the regression line of $y$ on $x$. [4]
\end{enumerate}

The athletics coach believes that, on average, the time taken by an athlete to run $200$ metres decreases between the beginning and the end of the year by more than $0.2$ seconds.

\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item Stating suitable hypotheses and assuming a normal distribution, test the coach's belief at the $10\%$ significance level. [8]
\end{enumerate}

\hfill \mbox{\textit{CAIE FP2 2017 Q11 [24]}}