CAIE FP2 2017 June — Question 6 5 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2017
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypePooled variance estimate calculation
DifficultyStandard +0.8 This question requires understanding of pooled variance estimation and involves algebraic manipulation of summary statistics. Students must recall the pooled variance formula, set up equations using the given summaries, and solve for N. While conceptually straightforward for Further Maths students familiar with hypothesis testing, the algebraic setup and manipulation across multiple samples requires careful work, placing it moderately above average difficulty.
Spec5.05c Hypothesis test: normal distribution for population mean

The independent variables \(X\) and \(Y\) have distributions with the same variance \(\sigma^2\). Random samples of \(N\) observations of \(X\) and \(2N\) observations of \(Y\) are taken, and the results are summarised by $$\Sigma x = 4, \quad \Sigma x^2 = 10, \quad \Sigma y = 8, \quad \Sigma y^2 = 102.$$ These data give a pooled estimate of \(10\) for \(\sigma^2\). Find \(N\). [5]

Question 6:
AnswerMarks Guidance
6(10 – 42/N + 102 – 82/2N) / (N + 2N – 2) (AEF) M1 A1
(confusing biased/unbiased estimates may still earn
M1)
AnswerMarks Guidance
112 – 48/N = 10 (3N – 2), 15N 2 – 66N + 24 = 0M1 A1 Equate to 10 and rearrange as quadratic
N = (66 ± 54) / 30 = 4A1 Solve quadratic for N, rejecting root 0⋅4
Total:5
QuestionAnswer Marks
Question 6:
6 | (10 – 42/N + 102 – 82/2N) / (N + 2N – 2) (AEF) | M1 A1 | State or find expression for pooled estimate of σ2
(confusing biased/unbiased estimates may still earn
M1)
112 – 48/N = 10 (3N – 2), 15N 2 – 66N + 24 = 0 | M1 A1 | Equate to 10 and rearrange as quadratic
N = (66 ± 54) / 30 = 4 | A1 | Solve quadratic for N, rejecting root 0⋅4
Total: | 5
Question | Answer | Marks | Guidance
The independent variables $X$ and $Y$ have distributions with the same variance $\sigma^2$. Random samples of $N$ observations of $X$ and $2N$ observations of $Y$ are taken, and the results are summarised by
$$\Sigma x = 4, \quad \Sigma x^2 = 10, \quad \Sigma y = 8, \quad \Sigma y^2 = 102.$$

These data give a pooled estimate of $10$ for $\sigma^2$. Find $N$. [5]

\hfill \mbox{\textit{CAIE FP2 2017 Q6 [5]}}