CAIE FP2 2012 June — Question 10 11 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2012
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChi-squared test of independence
TypeScaled sample, find minimum N
DifficultyStandard +0.8 This is a two-part chi-squared test question requiring standard contingency table analysis followed by a reverse problem finding the scaling factor N. The first part is routine A-level statistics (calculate expected frequencies, compute χ², compare to critical value), but the second part requires understanding that χ² scales linearly with sample size and working backwards from the critical value, which demands deeper conceptual insight beyond standard textbook exercises.
Spec5.06a Chi-squared: contingency tables

Random samples of employees are taken from two companies, \(A\) and \(B\). Each employee is asked which of three types of coffee (Cappuccino, Latte, Ground) they prefer. The results are shown in the following table.
CappuccinoLatteGround
Company \(A\)605232
Company \(B\)354031
Test, at the 5% significance level, whether coffee preferences of employees are independent of their company. [7] Larger random samples, consisting of \(N\) times as many employees from each company, are taken. In each company, the proportions of employees preferring the three types of coffee remain unchanged. Find the least possible value of \(N\) that would lead to the conclusion, at the 1% significance level, that coffee preferences of employees are not independent of their company. [4]

Question 10:
AnswerMarks
10Find expected values (to 1 d.p.): 54⋅72 52⋅992 36⋅288
(lose A1 if rounded to integers) 40⋅28 39⋅008 26⋅712 M1 A1
State (at least) null hypothesis (A.E.F.): H0: Preferences are independent B1
Calculate value of χ2 : χ2 = 0⋅5095 + 0⋅0186 + 0⋅5067
+ 0⋅6921 + 0⋅0252 + 0⋅6883
= 2⋅44 or 2⋅45 M1 A1
χ2
State or use correct tabular value (to 3
sf): χ 2, 0.95 2 = 5⋅99[1] B1
Conclusion consistent with values (A.E.F): Preferences are independent A1 √
C S a ta lc te u l o a r te u n se e w co v r a re lu c e t t χ a n b e u w l 2 a o r f χ χ 2 2 v : alue: χ χ n 2, e w 0. 2 9 9 = 2 = N × 9 χ ⋅2 2 1 M B 1 1
AnswerMarks
Find Nmin: N > 9⋅21/2⋅45, Nmin = 4 M1 A17
4[11]
Question 10:
10 | Find expected values (to 1 d.p.): 54⋅72 52⋅992 36⋅288
(lose A1 if rounded to integers) 40⋅28 39⋅008 26⋅712 M1 A1
State (at least) null hypothesis (A.E.F.): H0: Preferences are independent B1
Calculate value of χ2 : χ2 = 0⋅5095 + 0⋅0186 + 0⋅5067
+ 0⋅6921 + 0⋅0252 + 0⋅6883
= 2⋅44 or 2⋅45 M1 A1
χ2
State or use correct tabular value (to 3
sf): χ 2, 0.95 2 = 5⋅99[1] B1
Conclusion consistent with values (A.E.F): Preferences are independent A1 √
C S a ta lc te u l o a r te u n se e w co v r a re lu c e t t χ a n b e u w l 2 a o r f χ χ 2 2 v : alue: χ χ n 2, e w 0. 2 9 9 = 2 = N × 9 χ ⋅2 2 1 M B 1 1
Find Nmin: N > 9⋅21/2⋅45, Nmin = 4 M1 A1 | 7
4 | [11]
Random samples of employees are taken from two companies, $A$ and $B$. Each employee is asked which of three types of coffee (Cappuccino, Latte, Ground) they prefer. The results are shown in the following table.

\begin{center}
\begin{tabular}{|l|c|c|c|}
\hline
 & Cappuccino & Latte & Ground \\
\hline
Company $A$ & 60 & 52 & 32 \\
\hline
Company $B$ & 35 & 40 & 31 \\
\hline
\end{tabular}
\end{center}

Test, at the 5% significance level, whether coffee preferences of employees are independent of their company. [7]

Larger random samples, consisting of $N$ times as many employees from each company, are taken. In each company, the proportions of employees preferring the three types of coffee remain unchanged. Find the least possible value of $N$ that would lead to the conclusion, at the 1% significance level, that coffee preferences of employees are not independent of their company. [4]

\hfill \mbox{\textit{CAIE FP2 2012 Q10 [11]}}