Moderate -0.3 This is a straightforward application of the geometric distribution with standard formulas. Part (i) requires direct substitution into P(X=k) = (1-p)^(k-1)p, part (ii) is immediate recall that E(N)=1/p=100, and part (iii) involves solving (1-p)^n > 0.1 using logarithms—all routine procedures for this topic with no conceptual challenges or novel problem-solving required.
The probability that a particular type of light bulb is defective is 0.01. A large number of these bulbs are tested, one by one. Assuming independence, find the probability that the tenth bulb tested is the first to be found defective. [2]
The first defective bulb is the \(N\)th to be tested. Write down the value of E\((N)\). [1]
Find the least value of \(n\) such that P\((N < n)\) is greater than 0.9. [3]
The probability that a particular type of light bulb is defective is 0.01. A large number of these bulbs are tested, one by one. Assuming independence, find the probability that the tenth bulb tested is the first to be found defective. [2]
The first defective bulb is the $N$th to be tested. Write down the value of E$(N)$. [1]
Find the least value of $n$ such that P$(N < n)$ is greater than 0.9. [3]
\hfill \mbox{\textit{CAIE FP2 2012 Q6 [6]}}