CAIE Further Paper 2 2024 November — Question 3 7 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2024
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
DifficultyChallenging +1.8 This is a Further Maths arc length question requiring parametric differentiation, simplification of expressions involving exponentials and polynomials, and integration. While the calculus is standard, the algebraic manipulation to simplify √(dx/dt)² + (dy/dt)² into an integrable form requires careful work and insight. The 7-mark allocation reflects substantial computation, placing it well above average difficulty but not at the extreme end for Further Maths.
Spec1.07s Parametric and implicit differentiation4.08f Integrate using partial fractions

The curve \(C\) has parametric equations $$x = \frac{1}{2}e^{2t} - \frac{1}{3}t^3 - \frac{1}{2}, \quad y = 2e^t(t-1), \quad \text{for } 0 \leqslant t \leqslant 1.$$ Find the exact length of \(C\). [7]

Question 3:
AnswerMarks Guidance
3x=e2t −t2, y=2et +2(t−1)et =2tet B1B1
x2 + y2 = ( e2t −t2 )2 +4t2e2t =e4t +2t2e2t +t4 = ( e2t +t2 )2M1A1 Factorises x2 + y2.
 1 e2t +t2dt =1e2t +1t3 1
AnswerMarks Guidance
0 2 3  0M1A1 Applies correct formula for arc length.
= 1e2 −1
AnswerMarks
2 6A1
7
AnswerMarks Guidance
QuestionAnswer Marks
Question 3:
3 | x=e2t −t2, y=2et +2(t−1)et =2tet | B1B1 | Differentiates x and y with respect to t.
x2 + y2 = ( e2t −t2 )2 +4t2e2t =e4t +2t2e2t +t4 = ( e2t +t2 )2 | M1A1 | Factorises x2 + y2.
 1 e2t +t2dt =1e2t +1t3 1
0 2 3  0 | M1A1 | Applies correct formula for arc length.
= 1e2 −1
2 6 | A1
7
Question | Answer | Marks | Guidance
The curve $C$ has parametric equations
$$x = \frac{1}{2}e^{2t} - \frac{1}{3}t^3 - \frac{1}{2}, \quad y = 2e^t(t-1), \quad \text{for } 0 \leqslant t \leqslant 1.$$

Find the exact length of $C$. [7]

\hfill \mbox{\textit{CAIE Further Paper 2 2024 Q3 [7]}}