CAIE Further Paper 2 2024 November — Question 1 4 marks

Exam BoardCAIE
ModuleFurther Paper 2 (Further Paper 2)
Year2024
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration using inverse trig and hyperbolic functions
TypeStandard integral of 1/√(x²-a²)
DifficultyStandard +0.8 This is a standard inverse hyperbolic integration requiring recognition of the arccosh form and substitution u=x-5, followed by evaluation at limits. While it requires knowledge of a Further Maths formula and careful algebraic manipulation, it's a direct application of a known result with no novel problem-solving required. The 4-mark allocation and straightforward structure place it slightly above average difficulty.
Spec4.08h Integration: inverse trig/hyperbolic substitutions

Find the value of \(\int_6^7 \frac{1}{\sqrt{(x-5)^2-1}} \, dx\), giving your answer in the form \(\ln(a + \sqrt{b})\), where \(a\) and \(b\) are integers to be determined. [4]

Question 1:
AnswerMarks
17
 1 dx= cosh−1(x−5) 7
  
 (x−5)2 −12 6
AnswerMarks Guidance
6M1A1 Applies formula.
=cosh −1( 2 )−cosh −1( 1 )M1 Uses limits.
( )
AnswerMarks
=ln 2+ 3A1
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | 7
 1 dx= cosh−1(x−5) 7
  
 (x−5)2 −12 6
6 | M1A1 | Applies formula.
=cosh −1( 2 )−cosh −1( 1 ) | M1 | Uses limits.
( )
=ln 2+ 3 | A1
4
Question | Answer | Marks | Guidance
Find the value of $\int_6^7 \frac{1}{\sqrt{(x-5)^2-1}} \, dx$, giving your answer in the form $\ln(a + \sqrt{b})$, where $a$ and $b$ are integers to be determined. [4]

\hfill \mbox{\textit{CAIE Further Paper 2 2024 Q1 [4]}}