CAIE P3 2017 November — Question 9 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2017
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Parts
TypeStationary points then area/volume
DifficultyStandard +0.8 This question requires finding stationary points by differentiating a product (requiring product rule), then integrating by parts twice to find an area. Part (ii) is particularly demanding as it requires repeated integration by parts with an exponential function and careful algebraic manipulation to reach the exact form. The 5 marks and 'show that' format indicate substantial working, making this harder than a routine integration by parts question but not exceptionally difficult for P3 level.
Spec1.07n Stationary points: find maxima, minima using derivatives1.07q Product and quotient rules: differentiation1.08i Integration by parts

\includegraphics{figure_9} The diagram shows the curve \(y = (1 + x^2)\text{e}^{-\frac{3x}{4}}\) for \(x \geqslant 0\). The shaded region \(R\) is enclosed by the curve, the \(x\)-axis and the lines \(x = 0\) and \(x = 2\).
  1. Find the exact values of the \(x\)-coordinates of the stationary points of the curve. [4]
  2. Show that the exact value of the area of \(R\) is \(18 - \frac{42}{\text{e}}\). [5]

Question 9:

AnswerMarks Guidance
9(i)Use correct product or quotient rule M1
Obtain correct derivative in any formA1
Equate derivative to zero and obtain a 3 term quadratic equation in xM1
Obtain answers x=2± 3A1
4

AnswerMarks Guidance
9(ii)Integrate by parts and reach k(1+x2)e−1 2 x +l∫xe−1 2 x dx *M1
Obtain−2(1+x2)e−1 2 x +4∫xe−1 2 x dx, or equivalentA1
Complete the integration and obtain(−18−8x−2x2)e−1 2 x, or equivalentA1
Use limits x = 0 and x = 2 correctly, having fully integrated twice by partsDM1
Obtain the given answerA1
5
AnswerMarks Guidance
QuestionAnswer Marks
Question 9:
--- 9(i) ---
9(i) | Use correct product or quotient rule | M1
Obtain correct derivative in any form | A1
Equate derivative to zero and obtain a 3 term quadratic equation in x | M1
Obtain answers x=2± 3 | A1
4
--- 9(ii) ---
9(ii) | Integrate by parts and reach k(1+x2)e−1 2 x +l∫xe−1 2 x dx | *M1
Obtain−2(1+x2)e−1 2 x +4∫xe−1 2 x dx, or equivalent | A1
Complete the integration and obtain(−18−8x−2x2)e−1 2 x, or equivalent | A1
Use limits x = 0 and x = 2 correctly, having fully integrated twice by parts | DM1
Obtain the given answer | A1
5
Question | Answer | Marks
\includegraphics{figure_9}

The diagram shows the curve $y = (1 + x^2)\text{e}^{-\frac{3x}{4}}$ for $x \geqslant 0$. The shaded region $R$ is enclosed by the curve, the $x$-axis and the lines $x = 0$ and $x = 2$.

\begin{enumerate}[label=(\roman*)]
\item Find the exact values of the $x$-coordinates of the stationary points of the curve. [4]
\item Show that the exact value of the area of $R$ is $18 - \frac{42}{\text{e}}$. [5]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2017 Q9 [9]}}