CAIE P3 2006 June — Question 8 9 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2006
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration by Parts
TypeStationary points then area/volume
DifficultyStandard +0.3 Part (i) requires standard differentiation using product rule and solving for stationary points. Part (ii) is a straightforward application of integration by parts with u=ln x, though students must handle the limits carefully. Both parts are routine techniques with no novel insight required, making this slightly easier than average.
Spec1.07l Derivative of ln(x): and related functions1.07n Stationary points: find maxima, minima using derivatives1.08i Integration by parts

\includegraphics{figure_8} The diagram shows a sketch of the curve \(y = x^2\ln x\) and its minimum point \(M\). The curve cuts the \(x\)-axis at the point \((1, 0)\).
  1. Find the exact value of the \(x\)-coordinate of \(M\). [4]
  2. Use integration by parts to find the area of the shaded region enclosed by the curve, the \(x\)-axis and the line \(x = 4\). Give your answer correct to 2 decimal places. [5]

(i)
AnswerMarks Guidance
Use product ruleM1
Obtain derivative in any correct form e.g. \(\frac{x^{\frac{1}{2}}}{2} + x^{-1}\ln x\)A1
Equate derivative to zero and solve for \(\ln x\)M1
Obtain \(x = e^{-2}\) (or \(\frac{1}{e^2}\)) or equivalentA1 4
(ii) EITHER:
AnswerMarks
Attempt integration by parts with \(u = \ln x\)M1
Obtain \(\frac{2}{3}x^{\frac{3}{2}}\ln x - \int\frac{2}{3}y^{\frac{1}{2}}_{\frac{1}{x}}dx\), or equivalentA1
OR:
AnswerMarks Guidance
Attempt integration by parts with \(u = x^{\frac{1}{2}}\)M1
Obtain \(x^{\frac{1}{2}}(x\ln x - x) - \int(x\ln x - x) \cdot \frac{x^{-1}}{2}dx\)A1
Obtain indefinite integral \(\frac{2}{3}x^{\frac{3}{2}}\ln x - \frac{4}{9}x^{\frac{3}{2}}\), or equivalentA1
Use \(x = 1\) and \(x = 4\) as limitsM1
Obtain answer \(4.28\)A1 5
**(i)**

| Use product rule | M1 |
| Obtain derivative in any correct form e.g. $\frac{x^{\frac{1}{2}}}{2} + x^{-1}\ln x$ | A1 |
| Equate derivative to zero and solve for $\ln x$ | M1 |
| Obtain $x = e^{-2}$ (or $\frac{1}{e^2}$) or equivalent | A1 | 4 |

**(ii) EITHER:**

| Attempt integration by parts with $u = \ln x$ | M1 |
| Obtain $\frac{2}{3}x^{\frac{3}{2}}\ln x - \int\frac{2}{3}y^{\frac{1}{2}}_{\frac{1}{x}}dx$, or equivalent | A1 |

**OR:**

| Attempt integration by parts with $u = x^{\frac{1}{2}}$ | M1 |
| Obtain $x^{\frac{1}{2}}(x\ln x - x) - \int(x\ln x - x) \cdot \frac{x^{-1}}{2}dx$ | A1 |

| Obtain indefinite integral $\frac{2}{3}x^{\frac{3}{2}}\ln x - \frac{4}{9}x^{\frac{3}{2}}$, or equivalent | A1 |
| Use $x = 1$ and $x = 4$ as limits | M1 |
| Obtain answer $4.28$ | A1 | 5 |
\includegraphics{figure_8}

The diagram shows a sketch of the curve $y = x^2\ln x$ and its minimum point $M$. The curve cuts the $x$-axis at the point $(1, 0)$.

\begin{enumerate}[label=(\roman*)]
\item Find the exact value of the $x$-coordinate of $M$. [4]

\item Use integration by parts to find the area of the shaded region enclosed by the curve, the $x$-axis and the line $x = 4$. Give your answer correct to 2 decimal places. [5]
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2006 Q8 [9]}}