CAIE P1 2024 November — Question 5 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2024
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeFind curve from gradient
DifficultyModerate -0.8 This is a straightforward integration question requiring basic techniques: (a) solving a simple equation with fractional powers, and (b) integrating polynomial and root terms then finding the constant using a boundary condition. Both parts are routine textbook exercises with no problem-solving insight required, making it easier than average but not trivial due to the algebraic manipulation needed.
Spec1.08b Integrate x^n: where n != -1 and sums1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.08d Evaluate definite integrals: between limits

The equation of a curve is such that \(\frac{dy}{dx} = 4x - 3\sqrt{x} + 1\).
  1. Find the \(x\)-coordinate of the point on the curve at which the gradient is \(\frac{11}{2}\). [3]
  2. Given that the curve passes through the point \((4, 11)\), find the equation of the curve. [4]

Question 5:

AnswerMarks Guidance
5(a)Attempt correct process for solving 3-term quadratic equation in x M1
specified.
AnswerMarks Guidance
Obtain at least 2 x −3=0 or equivalentA1 Ignore 4 x + 3 = 0.
3
SC B1 for x = with no method shown for
2
solving the 3-term quadratic.
9 9
Conclude x= ignore
AnswerMarks Guidance
4 16A1 SC B1 if no method shown for solving the 3-term
quadratic.
Alternative Method for Q5(a)
9 81
3 x = 4x – → 16x2 – 45x + o.e and attempt correct process to solve
AnswerMarks
2 4M1
9 9
Obtain x = or
AnswerMarks Guidance
4 16A1 SC B1 if no method shown for solving the 3-term
quadratic.
9 9
x = ignore
AnswerMarks Guidance
4 16A1 SC B1 if no method shown for solving the 3-term
quadratic.
3
AnswerMarks Guidance
QuestionAnswer Marks

AnswerMarks
5(b)3
Integrate to obtain form k x2 +k x2 +k x where kk k 0
AnswerMarks
1 2 3 1 2 3M1
3
AnswerMarks Guidance
Obtain correct 2x2 −2x2 +x or equivalentA1 Allow unsimplified.
Substitute x=4 andy=11 to attempt value of cM1 Dependent on at least 2 correct terms involving x.
3
AnswerMarks Guidance
Obtain y=2x2 −2x2 +x−9A1 Must be simplified.
Allow ‘f(x) =’.
Allow y missing if y appears previously.
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 5:
--- 5(a) ---
5(a) | Attempt correct process for solving 3-term quadratic equation in x | M1 | Accept 8y2 – 6y – 9 → (2y – 3)(4y + 3), if y = √x
specified.
Obtain at least 2 x −3=0 or equivalent | A1 | Ignore 4 x + 3 = 0.
3
SC B1 for x = with no method shown for
2
solving the 3-term quadratic.
9 9
Conclude x= ignore
4 16 | A1 | SC B1 if no method shown for solving the 3-term
quadratic.
Alternative Method for Q5(a)
9 81
3 x = 4x – → 16x2 – 45x + o.e and attempt correct process to solve
2 4 | M1
9 9
Obtain x = or
4 16 | A1 | SC B1 if no method shown for solving the 3-term
quadratic.
9 9
x = ignore
4 16 | A1 | SC B1 if no method shown for solving the 3-term
quadratic.
3
Question | Answer | Marks | Guidance
--- 5(b) ---
5(b) | 3
Integrate to obtain form k x2 +k x2 +k x where kk k 0
1 2 3 1 2 3 | M1
3
Obtain correct 2x2 −2x2 +x or equivalent | A1 | Allow unsimplified.
Substitute x=4 andy=11 to attempt value of c | M1 | Dependent on at least 2 correct terms involving x.
3
Obtain y=2x2 −2x2 +x−9 | A1 | Must be simplified.
Allow ‘f(x) =’.
Allow y missing if y appears previously.
4
Question | Answer | Marks | Guidance
The equation of a curve is such that $\frac{dy}{dx} = 4x - 3\sqrt{x} + 1$.

\begin{enumerate}[label=(\alph*)]
\item Find the $x$-coordinate of the point on the curve at which the gradient is $\frac{11}{2}$. [3]

\item Given that the curve passes through the point $(4, 11)$, find the equation of the curve. [4]
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2024 Q5 [7]}}