CAIE P1 2023 June — Question 5 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2023
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeArea under curve with fractional/negative powers or roots
DifficultyModerate -0.3 This is a straightforward integration question requiring students to integrate powers of x (with fractional indices) between given limits. The integrand is already provided, the limits are clearly stated, and the technique is standard application of the power rule for integration. It's slightly easier than average because it's a direct single-method problem with no setup required, though the fractional powers require careful handling.
Spec1.08d Evaluate definite integrals: between limits1.08e Area between curve and x-axis: using definite integrals

\includegraphics{figure_5} The diagram shows the curve with equation \(y = 10x^{\frac{1}{2}} - \frac{5}{2}x^{\frac{3}{2}}\) for \(x > 0\). The curve meets the \(x\)-axis at the points \((0, 0)\) and \((4, 0)\). Find the area of the shaded region. [4]

Question 5:
AnswerMarks
5Where a candidate has misread a number in the question and used that value consistently throughout, provided that number does not alter the difficulty or
the method required, award all marks earned and deduct just 1 mark for the misread.
AnswerMarks
5  
 1 5 3 10 3 5 5  20 3 5
[10x2  x2]  x2  x2  x2 x2
  2    3  2 5   3 
AnswerMarks Guidance
 2  2 B1 B1 B1 for contents of each { } then ISW.
 20 
 their 832 0
 
AnswerMarks Guidance
 3 M1 Using limit(s) correctly in an integrated expression
(defined by one correct power). Minimum acceptable
160
working is their ( 32).
3
64 1
[Area of shaded region =] , 21 or 21.3[333…]
AnswerMarks Guidance
3 3A1 Condone the presence of π for the first 3 marks.
Condone using the limits the wrong way around for the M
mark and if 21.3 is corrected to 21.3 allow the A mark.
SC: if M0 scored SCB1 is available for correct final
answer
 1 5 3 
If 10x2  x2 21.3 and no integration seen B1 only.
 2 
 
4
AnswerMarks Guidance
QuestionAnswer Marks
Question 5:
5 | Where a candidate has misread a number in the question and used that value consistently throughout, provided that number does not alter the difficulty or
the method required, award all marks earned and deduct just 1 mark for the misread.
5 |   
 1 5 3 10 3 5 5  20 3 5
[10x2  x2]  x2  x2  x2 x2
  2    3  2 5   3 
 2  2  | B1 B1 | B1 for contents of each { } then ISW.
 20 
 their 832 0
 
 3  | M1 | Using limit(s) correctly in an integrated expression
(defined by one correct power). Minimum acceptable
160
working is their ( 32).
3
64 1
[Area of shaded region =] , 21 or 21.3[333…]
3 3 | A1 | Condone the presence of π for the first 3 marks.
Condone using the limits the wrong way around for the M
mark and if 21.3 is corrected to 21.3 allow the A mark.
SC: if M0 scored SCB1 is available for correct final
answer
 1 5 3 
If 10x2  x2 21.3 and no integration seen B1 only.
 2 
 
4
Question | Answer | Marks | Guidance
\includegraphics{figure_5}

The diagram shows the curve with equation $y = 10x^{\frac{1}{2}} - \frac{5}{2}x^{\frac{3}{2}}$ for $x > 0$. The curve meets the $x$-axis at the points $(0, 0)$ and $(4, 0)$.

Find the area of the shaded region. [4]

\hfill \mbox{\textit{CAIE P1 2023 Q5 [4]}}