Edexcel C4 2014 June — Question 1 7 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Year2014
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind tangent equation at point
DifficultyStandard +0.3 This is a standard implicit differentiation question requiring systematic application of the product rule and chain rule, followed by algebraic rearrangement to isolate dy/dx. Part (b) is routine substitution into the tangent formula. While it requires careful bookkeeping across multiple terms, it follows a well-practiced procedure with no novel insight needed, making it slightly easier than the average A-level question.
Spec1.07s Parametric and implicit differentiation

A curve \(C\) has the equation $$x^3 + 2xy - x - y^3 - 20 = 0$$
  1. [(a)] Find \(\frac{dy}{dx}\) in terms of \(x\) and \(y\). \hfill [5]
  2. [(b)] Find an equation of the tangent to \(C\) at the point \((3, -2)\), giving your answer in the form \(ax + by + c = 0\), where \(a\), \(b\) and \(c\) are integers. \hfill [2]

A curve $C$ has the equation
$$x^3 + 2xy - x - y^3 - 20 = 0$$

\begin{enumerate}
\item[(a)] Find $\frac{dy}{dx}$ in terms of $x$ and $y$. \hfill [5]

\item[(b)] Find an equation of the tangent to $C$ at the point $(3, -2)$, giving your answer in the form $ax + by + c = 0$, where $a$, $b$ and $c$ are integers. \hfill [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C4 2014 Q1 [7]}}