Pre-U Pre-U 9795/1 Specimen — Question 10 24 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
SessionSpecimen
Marks24
TopicComplex numbers 2
TypeExpress roots in trigonometric form
DifficultyChallenging +1.8 This is a substantial multi-part Further Maths question requiring de Moivre's theorem for multiple angle formulas, algebraic manipulation to extract a specific sine value, finding fifth roots in exponential form, and calculating a pentagon area using geometric reasoning. While the techniques are standard for Further Maths, the extended chain of reasoning and the final exact surd calculation elevate it above routine exercises.
Spec4.02b Express complex numbers: cartesian and modulus-argument forms4.02k Argand diagrams: geometric interpretation4.02q De Moivre's theorem: multiple angle formulae4.02r nth roots: of complex numbers

10
  1. Use de Moivre's theorem to prove that \(\sin 5 \theta \equiv s \left( 16 s ^ { 4 } - 20 s ^ { 2 } + 5 \right)\), where \(s = \sin \theta\), and deduce that \(\sin \frac { 2 \pi } { 5 } = \sqrt { \frac { 5 + \sqrt { 5 } } { 8 } }\). The complex number \(\omega = 16 ( - 1 + \mathrm { i } \sqrt { 3 } )\).
  2. State the value of \(| \omega |\) and find \(\arg \omega\) as a rational multiple of \(\pi\).
  3. (a) Determine the five roots of the equation \(z ^ { 5 } = \omega\), giving your answers in the form \(r \mathrm { e } ^ { \mathrm { i } \theta }\), where \(r > 0\) and \(- \pi < \theta \leq \pi\).
    (b) These five roots are represented in the complex plane by the points \(A , B , C , D\) and \(E\). Show these points on an Argand diagram, and find the area of the pentagon \(A B C D E\) in an exact surd form.

(i) \(\sin 5\theta = \text{Im}(\cos\theta + i\sin\theta)^5 = \text{Im}(c+is)^5\): M1
\((c+is)^5 = c^5 + 5c^4is + 10c^3i^2s^2 + 10c^2i^3s^3 + 5ci^4s^4 + i^5s^5\): M1
Im part \(= s(5c^4 - 10c^2s^2 + s^4)\): A1
\(= s\left(5(1-s^2)^2 - 10(1-s^2)s^2 + s^4\right)\): M1
\(= s(16s^4 - 20s^2 + 5)\), given answer legitimately: A1
\(\sin 5\theta = 0 \Rightarrow 5\theta = 0, \pm\pi, \pm 2\pi\), etc \(\Rightarrow \theta = 0, \pm\frac{\pi}{5}, \pm\frac{2\pi}{5}\), etc: M1
\(s^2 = \frac{20 \pm \sqrt{80}}{32} = \frac{5\pm\sqrt{5}}{8}\): M1
Since \(\frac{2\pi}{5}\) is acute and sine is an increasing function for acute angles,
\(s = \sin\frac{2\pi}{5} = \sqrt{\frac{5+\sqrt{5}}{8}}\), with explanation (allow "largest positive root wanted"): A1 [8]
AnswerMarks Guidance
(ii) \(\omega = 32\): B1
For use of \(\tan^{-1}(\sqrt{3})\): M1
For \(\arg\omega = \frac{2\pi}{3}\): A1 [3]
(iii)(a) \(z^5 = \left(32, \frac{-10\pi}{3}\right),\ \left(32, \frac{-4\pi}{3}\right),\ \left(32, \frac{2\pi}{3}\right),\ \left(32, \frac{8\pi}{3}\right),\ \left(32, \frac{14\pi}{3}\right)\)
For use of mods & args: M1; For considering at least two others \(\pm 2n\pi\): M1
\(\Rightarrow z = \left(2, \frac{-2\pi}{3}\right),\ \left(2, \frac{-4\pi}{15}\right),\ \left(2, \frac{2\pi}{15}\right),\ \left(2, \frac{8\pi}{15}\right),\ \left(2, \frac{14\pi}{15}\right)\)
ft \(\sqrt[5]{\text{mod}}\): B1; ft arg/5: M1; All correct: A1 [5]
(b) For 5 points on circle, centre \(O\), radius 2, equally spread out: B1
Area \(= 5 \times \frac{1}{2} \times 2 \times 2 \times \sin\frac{2\pi}{5}\): M1
\(= 10\sqrt{\frac{5+\sqrt{5}}{8}}\) or exact equivalent: A1 [3]
**(i)** $\sin 5\theta = \text{Im}(\cos\theta + i\sin\theta)^5 = \text{Im}(c+is)^5$: M1

$(c+is)^5 = c^5 + 5c^4is + 10c^3i^2s^2 + 10c^2i^3s^3 + 5ci^4s^4 + i^5s^5$: M1

Im part $= s(5c^4 - 10c^2s^2 + s^4)$: A1

$= s\left(5(1-s^2)^2 - 10(1-s^2)s^2 + s^4\right)$: M1

$= s(16s^4 - 20s^2 + 5)$, given answer legitimately: A1

$\sin 5\theta = 0 \Rightarrow 5\theta = 0, \pm\pi, \pm 2\pi$, etc $\Rightarrow \theta = 0, \pm\frac{\pi}{5}, \pm\frac{2\pi}{5}$, etc: M1

$s^2 = \frac{20 \pm \sqrt{80}}{32} = \frac{5\pm\sqrt{5}}{8}$: M1

Since $\frac{2\pi}{5}$ is acute and sine is an increasing function for acute angles,

$s = \sin\frac{2\pi}{5} = \sqrt{\frac{5+\sqrt{5}}{8}}$, with explanation (allow "largest positive root wanted"): A1 **[8]**

**(ii)** $|\omega| = 32$: B1

For use of $\tan^{-1}(\sqrt{3})$: M1

For $\arg\omega = \frac{2\pi}{3}$: A1 **[3]**

**(iii)(a)** $z^5 = \left(32, \frac{-10\pi}{3}\right),\ \left(32, \frac{-4\pi}{3}\right),\ \left(32, \frac{2\pi}{3}\right),\ \left(32, \frac{8\pi}{3}\right),\ \left(32, \frac{14\pi}{3}\right)$

For use of mods & args: M1; For considering at least two others $\pm 2n\pi$: M1

$\Rightarrow z = \left(2, \frac{-2\pi}{3}\right),\ \left(2, \frac{-4\pi}{15}\right),\ \left(2, \frac{2\pi}{15}\right),\ \left(2, \frac{8\pi}{15}\right),\ \left(2, \frac{14\pi}{15}\right)$

**ft** $\sqrt[5]{\text{mod}}$: B1; **ft** arg/5: M1; All correct: A1 **[5]**

**(b)** For 5 points on circle, centre $O$, radius 2, equally spread out: B1

Area $= 5 \times \frac{1}{2} \times 2 \times 2 \times \sin\frac{2\pi}{5}$: M1

$= 10\sqrt{\frac{5+\sqrt{5}}{8}}$ or exact equivalent: A1 **[3]**
10
\begin{enumerate}[label=(\roman*)]
\item Use de Moivre's theorem to prove that $\sin 5 \theta \equiv s \left( 16 s ^ { 4 } - 20 s ^ { 2 } + 5 \right)$, where $s = \sin \theta$, and deduce that $\sin \frac { 2 \pi } { 5 } = \sqrt { \frac { 5 + \sqrt { 5 } } { 8 } }$.

The complex number $\omega = 16 ( - 1 + \mathrm { i } \sqrt { 3 } )$.
\item State the value of $| \omega |$ and find $\arg \omega$ as a rational multiple of $\pi$.
\item (a) Determine the five roots of the equation $z ^ { 5 } = \omega$, giving your answers in the form $r \mathrm { e } ^ { \mathrm { i } \theta }$, where $r > 0$ and $- \pi < \theta \leq \pi$.\\
(b) These five roots are represented in the complex plane by the points $A , B , C , D$ and $E$. Show these points on an Argand diagram, and find the area of the pentagon $A B C D E$ in an exact surd form.
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9795/1  Q10 [24]}}