Pre-U Pre-U 9795/1 Specimen — Question 3 3 marks

Exam BoardPre-U
ModulePre-U 9795/1 (Pre-U Further Mathematics Paper 1)
SessionSpecimen
Marks3
Topic3x3 Matrices
TypeDeterminant calculation and singularity
DifficultyStandard +0.3 This is a straightforward multi-part question requiring determinant calculation (standard 3×3 formula), recognizing that singular matrices correspond to non-unique solutions, and solving a 3×3 system. All techniques are routine for Further Maths students with no novel insight required, making it slightly easier than average.
Spec4.03j Determinant 3x3: calculation4.03r Solve simultaneous equations: using inverse matrix4.03s Consistent/inconsistent: systems of equations

3
  1. Evaluate, in terms of \(k\), the determinant of the matrix \(\left( \begin{array} { r r r } 1 & 2 & 1 \\ - 3 & 5 & 8 \\ 6 & 12 & k \end{array} \right)\). Three planes have equations \(x + 2 y + z = 4 , - 3 x + 5 y + 8 z = 21\) and \(6 x + 12 y + k z = 31\).
  2. State the value of \(k\) for which these three planes do not meet at a single point.
  3. Find the coordinates of the point of intersection of the three planes when \(k = 7\).

(i) Method for Sarrus' Rule, or expanding by \(R_1\) e.g.: M1
\(\text{Det} = 11k - 66\): A1 [2]
(ii) \(k = 6\) ft from their Det \(= 0\): B1 [1]
(iii) *EITHER:* e.g. \(\circled{3} - 6 \times \circled{1} \Rightarrow z = 7\)
e.g. \(\circled{3} + 2 \times \circled{2} \Rightarrow 22y + 23z = 73 \Rightarrow 22y = -88 \Rightarrow y = -4\)
For a complete solution strategy: M1
e.g. \(x = 4 - 2y - z = 5\), for first correct: A1
\(x = 5,\ y = -4,\ z = 7\), for all 3 correct: A1
*OR:* \(\frac{1}{11}\begin{pmatrix}-61 & -2 & 11 \\ 69 & 1 & -11 \\ -66 & 0 & 11\end{pmatrix}\begin{pmatrix}4\\21\\31\end{pmatrix} = \begin{pmatrix}5\\-4\\7\end{pmatrix}\)
For complete method: M1; For correct inverse of the matrix of coefficients: B1; For correct answer: A1 [3]
**(i)** Method for Sarrus' Rule, or expanding by $R_1$ e.g.: M1

$\text{Det} = 11k - 66$: A1 **[2]**

**(ii)** $k = 6$ **ft** from their Det $= 0$: B1 **[1]**

**(iii)** *EITHER:* e.g. $\circled{3} - 6 \times \circled{1} \Rightarrow z = 7$

e.g. $\circled{3} + 2 \times \circled{2} \Rightarrow 22y + 23z = 73 \Rightarrow 22y = -88 \Rightarrow y = -4$

For a complete solution strategy: M1

e.g. $x = 4 - 2y - z = 5$, for first correct: A1

$x = 5,\ y = -4,\ z = 7$, for all 3 correct: A1

*OR:* $\frac{1}{11}\begin{pmatrix}-61 & -2 & 11 \\ 69 & 1 & -11 \\ -66 & 0 & 11\end{pmatrix}\begin{pmatrix}4\\21\\31\end{pmatrix} = \begin{pmatrix}5\\-4\\7\end{pmatrix}$

For complete method: M1; For correct inverse of the matrix of coefficients: B1; For correct answer: A1 **[3]**
3 (i) Evaluate, in terms of $k$, the determinant of the matrix $\left( \begin{array} { r r r } 1 & 2 & 1 \\ - 3 & 5 & 8 \\ 6 & 12 & k \end{array} \right)$.

Three planes have equations $x + 2 y + z = 4 , - 3 x + 5 y + 8 z = 21$ and $6 x + 12 y + k z = 31$.\\
(ii) State the value of $k$ for which these three planes do not meet at a single point.\\
(iii) Find the coordinates of the point of intersection of the three planes when $k = 7$.

\hfill \mbox{\textit{Pre-U Pre-U 9795/1  Q3 [3]}}