Pre-U Pre-U 9794/1 2012 Specimen — Question 2 5 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2012
SessionSpecimen
Marks5
TopicFactor & Remainder Theorem
TypeFully specified polynomial: verify factor and solve
DifficultyModerate -0.8 This is a straightforward application of the factor theorem requiring substitution to verify x=2 is a root, then polynomial division to find the quadratic factor, followed by solving a simple quadratic. It's below average difficulty as it's a standard textbook exercise with clear signposting and routine techniques throughout.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

2
  1. Show that \(x = 2\) is a root of the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).
  2. Hence solve the equation \(2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0\).

(i) Show \(f(2) = 0\) B1
(ii) Method shown e.g. division to get quadratic M1
Obtain two factors or roots A1
\((x-2)(2x-3)(x+3)\) A1
\(x = 2,\ \dfrac{3}{2},\ -3\) (follow through *their* factors) B1 ft
Total: 5 marks
**(i)** Show $f(2) = 0$ **B1**

**(ii)** Method shown e.g. division to get quadratic **M1**
Obtain two factors or roots **A1**
$(x-2)(2x-3)(x+3)$ **A1**
$x = 2,\ \dfrac{3}{2},\ -3$ (follow through *their* factors) **B1 ft**

**Total: 5 marks**
2 (i) Show that $x = 2$ is a root of the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.\\
(ii) Hence solve the equation $2 x ^ { 3 } - x ^ { 2 } - 15 x + 18 = 0$.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2012 Q2 [5]}}