Pre-U Pre-U 9794/1 2012 June — Question 3 6 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2012
SessionJune
Marks6
TopicTangents, normals and gradients
TypeFind stationary points
DifficultyModerate -0.8 This is a straightforward calculus question requiring basic differentiation of a polynomial and solving a quadratic equation to find stationary points. Both parts are standard textbook exercises with no problem-solving insight needed, making it easier than average but not trivial since it requires correct application of the quadratic formula or factorisation.
Spec1.07i Differentiate x^n: for rational n and sums1.07n Stationary points: find maxima, minima using derivatives

3 The equation of a curve is \(y = x ^ { 3 } + x ^ { 2 } - x + 3\).
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\).
  2. Hence find the coordinates of the stationary points on the curve.

Part (i)
- Attempt differentiation of at least one term: M1
- Obtain \(3x^2 + 2x - 1\): A1 [2]
Part (ii)
- State or imply their derivative equal to 0: B1
- Attempt to solve quadratic: M1
- Obtain \(x = -1\) and \(\frac{1}{3}\): A1
- Obtain \(y = 4\) and \(\frac{76}{27}\) (\(= 2.81\)) NIS: A1 [4]
[Total: 6]
**Part (i)**
- Attempt differentiation of at least one term: M1
- Obtain $3x^2 + 2x - 1$: A1 **[2]**

**Part (ii)**
- State or imply their derivative equal to 0: B1
- Attempt to solve quadratic: M1
- Obtain $x = -1$ and $\frac{1}{3}$: A1
- Obtain $y = 4$ and $\frac{76}{27}$ ($= 2.81$) NIS: A1 **[4]**

**[Total: 6]**
3 The equation of a curve is $y = x ^ { 3 } + x ^ { 2 } - x + 3$.\\
(i) Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$.\\
(ii) Hence find the coordinates of the stationary points on the curve.

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2012 Q3 [6]}}