SPS
SPS FM Pure
2020
February
— Question 7
6 marks
Exam Board
SPS
Module
SPS FM Pure (SPS FM Pure)
Year
2020
Session
February
Marks
6
Topic
Vectors: Lines & Planes
7
Find the shortest distance from the point (9, 5, 2) to the plane \(3 x + 2 y - 4 z = - 3\).
The vector equation of a second plane is given by
$$\boldsymbol { r } = \lambda \left( \begin{array} { l }
3
0
1
\end{array} \right) + \mu \left( \begin{array} { c }
1
- 1
- 2
\end{array} \right)$$
By finding the Cartesian equation of the plane, calculate the obtuse angle between this plane and the plane \(3 x + 2 y - 4 z = - 3\). [0pt]
[6]