OCR Further Additional Pure AS 2024 June — Question 1 2 marks

Exam BoardOCR
ModuleFurther Additional Pure AS (Further Additional Pure AS)
Year2024
SessionJune
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumber Theory
TypeBase conversion
DifficultyEasy -1.2 This is a straightforward base conversion requiring only the application of the standard formula N = 2×12⁴ + 8×12³ + A×12² + 3×12 + B. While it's from Further Maths, the mechanical calculation involves no problem-solving or conceptual insight—just arithmetic with powers of 12. Easier than average A-level questions.
Spec8.02a Number bases: conversion and arithmetic in base n

1 In this question you must show detailed reasoning. The number \(N\) is written as 28 A 3 B in base-12 form. Express \(N\) in decimal (base-10) form.

Question 1:
AnswerMarks Guidance
1(a) 205 = 7  29 + 2 i.e. q = 29, r = 2
[1]1.1
1(b) From (a), since 7 does not divide exactly into 205 (and 7 is
prime), 7 must divide 8666
AnswerMarks Guidance
If 7(205×8066), then, by Euclid’s Lemma … M1
A1
AnswerMarks
[2]2.4
2.2aUse of Euclid’s Lemma
No need to note that this is because r  0
Allow description of the “Euclid’s Lemma” condition
instead
A complete justification with assumption and
conclusion (hcf(7, 205) = 1)
Question 1:
1 | (a) | 205 = 7  29 + 2 i.e. q = 29, r = 2 | B1
[1] | 1.1
1 | (b) | From (a), since 7 does not divide exactly into 205 (and 7 is
prime), 7 must divide 8666
If 7 | (205×8066), then, by Euclid’s Lemma … | M1
A1
[2] | 2.4
2.2a | Use of Euclid’s Lemma
No need to note that this is because r  0
Allow description of the “Euclid’s Lemma” condition
instead
A complete justification with assumption and
conclusion (hcf(7, 205) = 1)
1 In this question you must show detailed reasoning.
The number $N$ is written as 28 A 3 B in base-12 form.

Express $N$ in decimal (base-10) form.

\hfill \mbox{\textit{OCR Further Additional Pure AS 2024 Q1 [2]}}