AQA Further Paper 3 Mechanics 2022 June — Question 2 1 marks

Exam BoardAQA
ModuleFurther Paper 3 Mechanics (Further Paper 3 Mechanics)
Year2022
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeFind power at constant speed
DifficultyEasy -1.8 This is a straightforward one-mark multiple choice question requiring direct application of the formula P = Fv. Students need only recognize that at constant speed, driving force equals resistive force (240 N), then multiply by speed (18 m/s) to get 4320 W. No problem-solving or multi-step reasoning required—pure formula recall with given values.
Spec6.02l Power and velocity: P = Fv

2 A car of mass 1200 kg is travelling at a constant speed of \(18 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) on a straight horizontal road. The car experiences a total resistive force of 240 newtons.
Calculate the power of the car's engine.
Circle your answer.
[0pt] [1 mark]
900 W
4320 W
16000 W
21600 W

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(4320 \text{ W}\)B1 (AO1.1b) Circles correct answer
Total: 1
## Question 2:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $4320 \text{ W}$ | B1 (AO1.1b) | Circles correct answer |
| **Total: 1** | | |

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2 A car of mass 1200 kg is travelling at a constant speed of $18 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ on a straight horizontal road.

The car experiences a total resistive force of 240 newtons.\\
Calculate the power of the car's engine.\\
Circle your answer.\\[0pt]
[1 mark]\\
900 W\\
4320 W\\
16000 W\\
21600 W

\hfill \mbox{\textit{AQA Further Paper 3 Mechanics 2022 Q2 [1]}}