9 Two blocks have square cross sections.
One block has mass 9 kg and its cross section has sides of length 20 cm
The other block has mass 1 kg and its cross section has sides of length 4 cm
The blocks are fixed together to form the composite body shown in Figure 1.
\begin{figure}[h]
\captionsetup{labelformat=empty}
\caption{Figure 1}
\includegraphics[alt={},max width=\textwidth]{0afe3ff2-0af5-4aeb-98c5-1346fa803388-13_570_492_717_776}
\end{figure}
9
- Find the distance of the centre of mass of the composite body from \(A F\)
[0pt]
[2 marks]
Question 9 continues on the next page
9 - A uniform rod has mass 12 kg and length 1 metre.
One end of the rod rests against a smooth vertical wall.
The other end of the rod rests on the composite body at point \(B\)
The composite body is on a horizontal surface.
The coefficient of friction between the composite body and the horizontal surface is 0.3
The angle between the rod and \(A B\) is \(60 ^ { \circ }\)
A particle of mass \(m \mathrm {~kg}\) is fixed to the rod at a distance of 75 cm from \(B\)
The rod, particle and composite body are shown in Figure 2.
\begin{figure}[h]
\captionsetup{labelformat=empty}
\caption{Figure 2}
\includegraphics[alt={},max width=\textwidth]{0afe3ff2-0af5-4aeb-98c5-1346fa803388-14_939_1020_1133_511}
\end{figure}
9 - Write down the magnitude of the vertical reaction force acting on the rod at \(B\) in terms of \(m\) and \(g\)
[0pt]
[1 mark]
9
- (ii) Show that the magnitude of the horizontal reaction force acting on the rod at \(B\) is
$$\frac { g ( 6 + 0.75 m ) } { \sqrt { 3 } }$$
9
- (iii) Find the maximum value of \(m\) for which the composite body does not slide or topple.
Fully justify your answer.