AQA Further Paper 3 Mechanics 2020 June — Question 2 1 marks

Exam BoardAQA
ModuleFurther Paper 3 Mechanics (Further Paper 3 Mechanics)
Year2020
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAdvanced work-energy problems
TypeWork done by non-constant force integration
DifficultyStandard +0.3 This is a straightforward application of the work-energy formula W = ∫F dx with a simple exponential function. Students need only recall that work = ∫T de from 0.2 to 0.4, giving ∫20e de = 10e² evaluated at the limits, yielding 10(0.16 - 0.04) = 1.2J. The integration is elementary and the answer is multiple choice, making this easier than average despite being a Further Maths mechanics question.
Spec6.02c Work by variable force: using integration

2 The tension, \(T\) newtons, in a spring is given by \(T = 20 e\), where \(e\) metres is the extension of the spring. Calculate the work done when the extension is increased from 0.2 metres to 0.4 metres. Circle your answer.
[0pt] [1 mark]
0.4 J 0.9 J 1.2 J 1.6 J

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(1.2\) JB1 Circles correct answer
## Question 2:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $1.2$ J | B1 | Circles correct answer |
2 The tension, $T$ newtons, in a spring is given by $T = 20 e$, where $e$ metres is the extension of the spring.

Calculate the work done when the extension is increased from 0.2 metres to 0.4 metres.

Circle your answer.\\[0pt]
[1 mark]\\
0.4 J 0.9 J 1.2 J 1.6 J

\hfill \mbox{\textit{AQA Further Paper 3 Mechanics 2020 Q2 [1]}}