Moderate -0.8 This is a straightforward centre of mass calculation with three components (two particles and a uniform rod). Students need only apply the standard formula with clearly given masses and positions, requiring basic arithmetic but no problem-solving insight or multi-step reasoning.
1 A rigid rod, \(A B\), has mass 2 kg and length 4 metres.
Two particles of masses 5 kg and 3 kg are fixed to \(A\) and \(B\) respectively to create a composite body, as shown in the diagram.
\includegraphics[max width=\textwidth, alt={}, center]{b0d0c552-71cb-4e5a-b545-de8a9052def0-02_120_730_769_653}
Find the distance of the centre of mass of the composite body from \(B\).
Circle your answer.
1.5 metres
1.6 metres
2.4 metres
2.5 metres
1 A rigid rod, $A B$, has mass 2 kg and length 4 metres.\\
Two particles of masses 5 kg and 3 kg are fixed to $A$ and $B$ respectively to create a composite body, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{b0d0c552-71cb-4e5a-b545-de8a9052def0-02_120_730_769_653}
Find the distance of the centre of mass of the composite body from $B$.
Circle your answer.\\
1.5 metres\\
1.6 metres\\
2.4 metres\\
2.5 metres
\hfill \mbox{\textit{AQA Further Paper 3 Mechanics 2020 Q1 [1]}}