Question 1 - A-Level Maths

AQA Further Paper 3 Statistics 2020 June — Question 1 1 marks

Exam Board	AQA
Module	Further Paper 3 Statistics (Further Paper 3 Statistics)
Year	2020
Session	June
Marks	1
Paper	Download PDF ↗
Mark scheme	Download PDF ↗
Topic	Continuous Uniform Random Variables
Type	Calculate simple probabilities
Difficulty	Easy -1.2 This is a straightforward application of the uniform distribution definition requiring only recognition that P(X ≥ 3) = (6-3) × (1/5) = 3/5. It's a single-step calculation with multiple choice answers provided, making it easier than average even for Further Maths statistics.
Spec	5.03a Continuous random variables: pdf and cdf

1 The continuous random variable $X$ has probability density function $$f ( x ) = \begin{cases} \frac { 1 } { 5 } & 1 \leq x \leq 6 \\ 0 & \text { otherwise } \end{cases}$$ Find $\mathrm { P } ( X \geq 3 )$ Circle your answer. $\frac { 1 } { 5 } \quad \frac { 2 } { 5 } \quad \frac { 3 } { 5 } \quad \frac { 4 } { 5 }$

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Question 1:

Answer	Marks	Guidance
Answer	Marks	Guidance
$\dfrac{3}{5}$	B1	Circles correct answer

Total: 1 mark

## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\dfrac{3}{5}$ | B1 | Circles correct answer |

**Total: 1 mark**

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1 The continuous random variable $X$ has probability density function

$$f ( x ) = \begin{cases} \frac { 1 } { 5 } & 1 \leq x \leq 6 \\ 0 & \text { otherwise } \end{cases}$$

Find $\mathrm { P } ( X \geq 3 )$\\
Circle your answer.

$\frac { 1 } { 5 } \quad \frac { 2 } { 5 } \quad \frac { 3 } { 5 } \quad \frac { 4 } { 5 }$

\hfill \mbox{\textit{AQA Further Paper 3 Statistics 2020 Q1 [1]}}

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