AQA Further Paper 2 2020 June — Question 11

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2020
SessionJune
TopicTaylor series
TypeEvaluate limit using series

11
  1. Starting from the series given in the formulae booklet, show that the general term of the Maclaurin series for $$\frac { \sin x } { x } - \cos x$$ is $$( - 1 ) ^ { r + 1 } \frac { 2 r } { ( 2 r + 1 ) ! } x ^ { 2 r }$$ 11
  2. Show that $$\lim _ { x \rightarrow 0 } \left[ \frac { \frac { \sin x } { x } - \cos x } { 1 - \cos x } \right] = \frac { 2 } { 3 }$$