Question 3 - A-Level Maths

Exam Board	AQA
Module	Further Paper 2 (Further Paper 2)
Year	2020
Session	June
Topic	Differentiating Transcendental Functions

3 Find the gradient of the tangent to the curve $$y = \sin ^ { - 1 } x$$ at the point where $x = \frac { 1 } { 5 }$
Circle your answer.

$\frac { 5 \sqrt { 6 } } { 12 }$

$\frac { 2 \sqrt { 6 } } { 5 }$

$\frac { 4 \sqrt { 3 } } { 25 }$

$\frac { 25 } { 24 }$