Easy -1.8 This is a straightforward substitution question requiring only direct calculation from a given probability distribution. Students simply substitute x=3 and x=4 into the formula and add: P(X≥3) = (5-3)/10 + (5-4)/10 = 0.2 + 0.1 = 0.3. No problem-solving, conceptual understanding, or multi-step reasoning required—pure mechanical computation with a multiple-choice format that further reduces difficulty.
1 The discrete random variable \(X\) has the following probability distribution function
$$\mathrm { P } ( X = x ) = \begin{cases} \frac { 5 - x } { 10 } & x = 1,2,3,4 \\ 0 & \text { otherwise } \end{cases}$$
Find \(\mathrm { P } ( X \geq 3 )\)
Circle your answer.
0.1
0.15
0.2
0.3
1 The discrete random variable $X$ has the following probability distribution function
$$\mathrm { P } ( X = x ) = \begin{cases} \frac { 5 - x } { 10 } & x = 1,2,3,4 \\ 0 & \text { otherwise } \end{cases}$$
Find $\mathrm { P } ( X \geq 3 )$\\
Circle your answer.\\
0.1\\
0.15\\
0.2\\
0.3
\hfill \mbox{\textit{AQA Further AS Paper 2 Statistics 2019 Q1 [1]}}