Given
$$\frac { x + 7 } { x + 1 } \leq x + 1$$
show that
$$\frac { ( x + a ) ( x + b ) } { x + c } \geq 0$$
where \(a , b\), and \(c\) are integers to be found.
14
Briefly explain why this statement is incorrect.
$$\frac { ( x + p ) ( x + q ) } { x + r } \geq 0 \Leftrightarrow ( x + p ) ( x + q ) ( x + r ) \geq 0$$
14