AQA Further AS Paper 1 2020 June — Question 13

Exam BoardAQA
ModuleFurther AS Paper 1 (Further AS Paper 1)
Year2020
SessionJune
TopicVectors 3D & Lines

13 Line \(l _ { 1 }\) has equation $$\frac { x - 2 } { 3 } = \frac { 1 - 2 y } { 4 } = - z$$ and line \(l _ { 2 }\) has equation $$\mathbf { r } = \left[ \begin{array} { c } - 7
4
- 2 \end{array} \right] + \mu \left[ \begin{array} { c } 12
a + 3
2 b \end{array} \right]$$ 13
  1. In the case when \(l _ { 1 }\) and \(l _ { 2 }\) are parallel, show that \(a = - 11\) and find the value of \(b\).
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