Easy -1.8 This is a trivial application of the additive property of definite integrals requiring only one step: recognizing that ∫₀⁶ f(x)dx = ∫₀³ f(x)dx + ∫₃⁶ f(x)dx, then substituting 20 = ∫₀³ f(x)dx + (-10) to get 30. This is pure recall with minimal calculation, significantly easier than typical A-level questions.
2 It is given that
$$\int _ { 0 } ^ { 6 } \mathrm { f } ( x ) \mathrm { d } x = 20 \text { and } \int _ { 3 } ^ { 6 } \mathrm { f } ( x ) \mathrm { d } x = - 10$$
Find the value of \(\int _ { 0 } ^ { 3 } \mathrm { f } ( x ) \mathrm { d } x\)
Circle your answer.
\(- 30 - 101030\)
2 It is given that
$$\int _ { 0 } ^ { 6 } \mathrm { f } ( x ) \mathrm { d } x = 20 \text { and } \int _ { 3 } ^ { 6 } \mathrm { f } ( x ) \mathrm { d } x = - 10$$
Find the value of $\int _ { 0 } ^ { 3 } \mathrm { f } ( x ) \mathrm { d } x$\\
Circle your answer.
$- 30 - 101030$
\hfill \mbox{\textit{AQA Paper 2 2023 Q2 [1]}}