OCR H240/03 — Question 6 7 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Marks7
PaperDownload PDF ↗
TopicStationary points and optimisation
TypeDetermine constant from stationary point condition
DifficultyStandard +0.3 This is a straightforward stationary points question requiring differentiation, substituting x=-2 into dy/dx=0 to find k, then finding the second derivative to identify the inflection point. All steps are standard A-level techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.07i Differentiate x^n: for rational n and sums1.07n Stationary points: find maxima, minima using derivatives1.07p Points of inflection: using second derivative

6 A curve has equation \(y = x ^ { 2 } + k x - 4 x ^ { - 1 }\) where \(k\) is a constant. Given that the curve has a minimum point when \(x = - 2\)
  • find the value of \(k\)
  • show that the curve has a point of inflection which is not a stationary point.

6 A curve has equation $y = x ^ { 2 } + k x - 4 x ^ { - 1 }$ where $k$ is a constant.

Given that the curve has a minimum point when $x = - 2$

\begin{itemize}
  \item find the value of $k$
  \item show that the curve has a point of inflection which is not a stationary point.
\end{itemize}

\hfill \mbox{\textit{OCR H240/03  Q6 [7]}}