OCR H240/03 — Question 3 4 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Marks4
PaperDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeSolve trigonometric equation to find exact trigonometric ratio
DifficultyStandard +0.8 This question requires using the double angle formula (sin 2x = 2sin x cos x), rearranging to form a quadratic in sin x or cos x, and solving to find an exact value. While it involves multiple steps and the double angle identity, it's a fairly standard technique taught in A-level. The constraint to exact values and the need to manipulate the equation elevates it slightly above average difficulty, but it remains a recognizable problem type that students practice regularly.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

3 In this question you must show detailed reasoning. Given that \(5 \sin 2 x = 3 \cos x\), where \(0 ^ { \circ } < x < 90 ^ { \circ }\), find the exact value of \(\sin x\).

3 In this question you must show detailed reasoning.
Given that $5 \sin 2 x = 3 \cos x$, where $0 ^ { \circ } < x < 90 ^ { \circ }$, find the exact value of $\sin x$.

\hfill \mbox{\textit{OCR H240/03  Q3 [4]}}