OCR D2 — Question 1 8 marks

Exam BoardOCR
ModuleD2 (Decision Mathematics 2)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicThe Simplex Algorithm
TypePerform one Simplex iteration
DifficultyModerate -0.8 This is a routine, procedural Simplex algorithm question requiring standard mechanical steps: setting up the initial tableau, performing one pivot operation as directed, and reading off the solution. It tests only recall and execution of the algorithm with no problem-solving or insight required, making it easier than average A-level material.
Spec7.07a Simplex tableau: initial setup in standard format7.07b Simplex iterations: pivot choice and row operations7.07c Interpret simplex: values of variables, slack, and objective7.07d Simplex terminology: basic feasible solution, basic/non-basic variable7.07e Graphical interpretation: iterations as edges of convex polygon7.07f Algebraic interpretation: explain simplex calculations7.07g

  1. A linear programming problem is defined as follows:
$$\begin{array} { l l } \text { Maximise } & P = 3 x + 3 y + 4 z \\ \text { subject to } & x + 2 y + z \leq 30 \\ & 5 x + y + 3 z \leq 60 \\ \text { and } & x \geq 0 , y \geq 0 , z \geq 0 . \end{array}$$
  1. Display the problem in a Simplex Tableau.
  2. Starting with a pivot chosen from the \(z\)-column, perform one iteration of your tableau.
  3. Write down the resulting values of \(x , y , z\) and \(P\) and state with a reason whether or not these values give an optimal solution.

\begin{enumerate}
  \item A linear programming problem is defined as follows:
\end{enumerate}

$$\begin{array} { l l } 
\text { Maximise } & P = 3 x + 3 y + 4 z \\
\text { subject to } & x + 2 y + z \leq 30 \\
& 5 x + y + 3 z \leq 60 \\
\text { and } & x \geq 0 , y \geq 0 , z \geq 0 .
\end{array}$$

(a) Display the problem in a Simplex Tableau.\\
(b) Starting with a pivot chosen from the $z$-column, perform one iteration of your tableau.\\
(c) Write down the resulting values of $x , y , z$ and $P$ and state with a reason whether or not these values give an optimal solution.\\

\hfill \mbox{\textit{OCR D2  Q1 [8]}}