AQA D1 2007 January — Question 7 14 marks

Exam BoardAQA
ModuleD1 (Decision Mathematics 1)
Year2007
SessionJanuary
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoute Inspection
TypeCombined Dijkstra and route inspection
DifficultyStandard +0.3 This is a straightforward application of two standard D1 algorithms (Dijkstra and route inspection) with minimal problem-solving required. Part (a) is routine Dijkstra execution, part (b)(i) is simple inspection of a small network, and part (b)(ii) is textbook route inspection (identify odd vertices, pair them optimally, add to total). The question provides the sum of all edges and requires only mechanical application of learned procedures, making it slightly easier than average for A-level.
Spec7.04a Shortest path: Dijkstra's algorithm7.04e Route inspection: Chinese postman, pairing odd nodes

7 [Figure 2, printed on the insert, is provided for use in this question.]
The network shows the times, in seconds, taken by Craig to walk along walkways connecting ten hotels in Las Vegas. \includegraphics[max width=\textwidth, alt={}, center]{e47eb41e-0a4b-4865-a8ff-6c9978495ee0-07_1435_1267_525_351} The total of all the times in the diagram is 2280 seconds.
    1. Craig is staying at the Circus ( \(C\) ) and has to visit the Oriental ( \(O\) ). Use Dijkstra's algorithm on Figure 2 to find the minimum time to walk from \(C\) to \(O\).
    2. Write down the corresponding route.
    1. Find, by inspection, the shortest time to walk from \(A\) to \(M\).
    2. Craig intends to walk along all the walkways. Find the minimum time for Craig to walk along every walkway and return to his starting point.

7(a)(i)
AnswerMarks Guidance
Diagram with SCA; 4 values at \(I\); 2 values at \(M\); 2 values at \(O\)M1, M1, M1, M1, A1, B1 465 at \(O\) (6 marks total)
7(a)(ii)
AnswerMarks Guidance
CASINOB1 Or ONISAC (1 mark total)
7(b)(i)
AnswerMarks Guidance
\(A \to M = 255\)B1 (1 mark total)
7(b)(ii)
AnswerMarks Guidance
Odds \((C, A, S, M)\) with \(CA + SM = 270\), \(CS + AM = 390\), \(CM + AS = 390\), Min \(2280 + 270 = 2550\)M1, A3, M1, A1 PI; (−1 EE) 2280 + their best pairing; SC 2/6 for answer 2550 with no working (6 marks total)
**7(a)(i)**
| Diagram with SCA; 4 values at $I$; 2 values at $M$; 2 values at $O$ | M1, M1, M1, M1, A1, B1 | 465 at $O$ (6 marks total) |

**7(a)(ii)**
| CASINO | B1 | Or ONISAC (1 mark total) |

**7(b)(i)**
| $A \to M = 255$ | B1 | (1 mark total) |

**7(b)(ii)**
| Odds $(C, A, S, M)$ with $CA + SM = 270$, $CS + AM = 390$, $CM + AS = 390$, Min $2280 + 270 = 2550$ | M1, A3, M1, A1 | PI; (−1 EE) 2280 + their best pairing; SC 2/6 for answer 2550 with no working (6 marks total) |
7 [Figure 2, printed on the insert, is provided for use in this question.]\\
The network shows the times, in seconds, taken by Craig to walk along walkways connecting ten hotels in Las Vegas.\\
\includegraphics[max width=\textwidth, alt={}, center]{e47eb41e-0a4b-4865-a8ff-6c9978495ee0-07_1435_1267_525_351}

The total of all the times in the diagram is 2280 seconds.
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Craig is staying at the Circus ( $C$ ) and has to visit the Oriental ( $O$ ).

Use Dijkstra's algorithm on Figure 2 to find the minimum time to walk from $C$ to $O$.
\item Write down the corresponding route.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Find, by inspection, the shortest time to walk from $A$ to $M$.
\item Craig intends to walk along all the walkways. Find the minimum time for Craig to walk along every walkway and return to his starting point.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA D1 2007 Q7 [14]}}