AQA FP1 2005 January — Question 6 8 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2005
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeFind general solution of trig equation
DifficultyStandard +0.3 This is a straightforward Further Pure 1 question requiring standard technique: recognize 1/√2 = cos(π/4), solve the compound angle equation using the general solution formula cos(θ)=cos(α) gives θ=±α+2nπ, then count roots in an interval. While it's FP1, it follows a routine algorithmic approach with exact values that students practice extensively.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

6 The angle \(x\) radians satisfies the equation $$\cos \left( 2 x + \frac { \pi } { 6 } \right) = \frac { 1 } { \sqrt { 2 } }$$
  1. Find the general solution of this equation, giving the roots as exact values in terms of \(\pi\).
  2. Find the number of roots of the equation which lie between 0 and \(2 \pi\).

Question 6:
Part (a)
AnswerMarks Guidance
Attempt at \(\cos^{-1}\frac{1}{\sqrt{2}}\)M1 Allow degrees or decimals
\(\frac{\pi}{4}\) appearing in solutionA1 Must be exact
Introduction of \(\pm\)M1
Introduction of \(\ldots + 2n\pi\)M1 Or \(360n\)
Making \(x\) the subjectM1 From \(2x + \frac{\pi}{6} = kn\pi + \alpha\) (or \(\pm\alpha\))
\(x = -\frac{\pi}{12} \pm \frac{\pi}{8} + n\pi\)A1 (6 marks) OE
Part (b)
AnswerMarks Guidance
Number of roots is 4M1A1ft (2 marks) M1 e.g. for answer consistent with candidate's general solution
## Question 6:

**Part (a)**
Attempt at $\cos^{-1}\frac{1}{\sqrt{2}}$ | M1 | Allow degrees or decimals
$\frac{\pi}{4}$ appearing in solution | A1 | Must be exact
Introduction of $\pm$ | M1 |
Introduction of $\ldots + 2n\pi$ | M1 | Or $360n$
Making $x$ the subject | M1 | From $2x + \frac{\pi}{6} = kn\pi + \alpha$ (or $\pm\alpha$)
$x = -\frac{\pi}{12} \pm \frac{\pi}{8} + n\pi$ | A1 (6 marks) | OE

**Part (b)**
Number of roots is 4 | M1A1ft (2 marks) | M1 e.g. for answer consistent with candidate's general solution

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6 The angle $x$ radians satisfies the equation

$$\cos \left( 2 x + \frac { \pi } { 6 } \right) = \frac { 1 } { \sqrt { 2 } }$$
\begin{enumerate}[label=(\alph*)]
\item Find the general solution of this equation, giving the roots as exact values in terms of $\pi$.
\item Find the number of roots of the equation which lie between 0 and $2 \pi$.
\end{enumerate}

\hfill \mbox{\textit{AQA FP1 2005 Q6 [8]}}