Moderate -0.8 This is a straightforward application of the power formula P = Fv where F is the driving force. Students need to resolve forces parallel to the incline (weight component + resistance) at constant speed, then multiply by velocity. It's a standard M2 exercise with clear given values and routine calculations, making it easier than average.
5 A train, of mass 600 tonnes, travels at constant speed up a slope inclined at an angle \(\theta\) to the horizontal, where \(\sin \theta = \frac { 1 } { 40 }\). The speed of the train is \(24 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and it experiences total resistance forces of 200000 N .
Find the power produced by the train, giving your answer in kilowatts.
5 A train, of mass 600 tonnes, travels at constant speed up a slope inclined at an angle $\theta$ to the horizontal, where $\sin \theta = \frac { 1 } { 40 }$. The speed of the train is $24 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and it experiences total resistance forces of 200000 N .
Find the power produced by the train, giving your answer in kilowatts.
\hfill \mbox{\textit{AQA M2 2009 Q5 [6]}}