AQA M2 2009 June — Question 7 10 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2009
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 2
TypeParticle on outer surface of cylinder
DifficultyStandard +0.3 This is a standard circular motion problem requiring energy conservation and Newton's second law in the radial direction. Part (a) is a 'show that' derivation following a routine method, and part (b) involves setting the normal reaction to zero—a very common exam technique. The question is slightly easier than average because the method is well-practiced and the algebra is straightforward.
Spec6.02i Conservation of energy: mechanical energy principle6.05d Variable speed circles: energy methods6.05e Radial/tangential acceleration

7 In crazy golf, a golf ball is hit so that it starts to move in a vertical circle on the inside of a smooth cylinder. Model the golf ball as a particle, \(P\), of mass \(m\). The circular path of the golf ball has radius \(a\) and centre \(O\). At time \(t\), the angle between \(O P\) and the horizontal is \(\theta\), as shown in the diagram. The golf ball has speed \(u\) at the lowest point of its circular path. \includegraphics[max width=\textwidth, alt={}, center]{9cfa110c-ee11-447a-b21a-3f436432e27d-6_739_742_719_641}
  1. Show that, while the golf ball is in contact with the cylinder, the reaction of the cylinder on the golf ball is $$\frac { m u ^ { 2 } } { a } - 3 m g \sin \theta - 2 m g$$
  2. Given that \(u = \sqrt { 3 a g }\), the golf ball will not complete a vertical circle inside the cylinder. Find the angle which \(O P\) makes with the horizontal when the golf ball leaves the surface of the cylinder.
    (4 marks)

7 In crazy golf, a golf ball is hit so that it starts to move in a vertical circle on the inside of a smooth cylinder.

Model the golf ball as a particle, $P$, of mass $m$. The circular path of the golf ball has radius $a$ and centre $O$. At time $t$, the angle between $O P$ and the horizontal is $\theta$, as shown in the diagram.

The golf ball has speed $u$ at the lowest point of its circular path.\\
\includegraphics[max width=\textwidth, alt={}, center]{9cfa110c-ee11-447a-b21a-3f436432e27d-6_739_742_719_641}
\begin{enumerate}[label=(\alph*)]
\item Show that, while the golf ball is in contact with the cylinder, the reaction of the cylinder on the golf ball is

$$\frac { m u ^ { 2 } } { a } - 3 m g \sin \theta - 2 m g$$
\item Given that $u = \sqrt { 3 a g }$, the golf ball will not complete a vertical circle inside the cylinder. Find the angle which $O P$ makes with the horizontal when the golf ball leaves the surface of the cylinder.\\
(4 marks)
\end{enumerate}

\hfill \mbox{\textit{AQA M2 2009 Q7 [10]}}