AQA M1 2007 June — Question 2 5 marks

Exam BoardAQA
ModuleM1 (Mechanics 1)
Year2007
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCoalescence collision
DifficultyModerate -0.8 This is a straightforward application of conservation of momentum in 2D with coalescence. Students simply apply m₁v₁ + m₂v₂ = (m₁+m₂)v for each component, then calculate magnitude. It's a standard textbook exercise requiring only direct formula application with no problem-solving insight or geometric complexity.
Spec1.10a Vectors in 2D: i,j notation and column vectors6.03a Linear momentum: p = mv6.03c Momentum in 2D: vector form6.03d Conservation in 2D: vector momentum

2 Two particles, \(A\) and \(B\), are moving on a smooth horizontal surface. Particle \(A\) has mass 2 kg and velocity \(\left[ \begin{array} { r } 3 \\ - 2 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\). Particle \(B\) has mass 3 kg and velocity \(\left[ \begin{array} { r } - 4 \\ 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\). The two particles collide, and they coalesce during the collision.
  1. Find the velocity of the combined particles after the collision.
  2. Find the speed of the combined particles after the collision.

2(a)
AnswerMarks Guidance
\(2\begin{bmatrix} 3 \\ -2 \end{bmatrix} + 3\begin{bmatrix} -4 \\ 1 \end{bmatrix} = 5\mathbf{v}\)M1 Three term vector equation, with a '+' sign, for conservation of momentum
A1Correct equation. Deduct this first A mark for use of \(mg\)
\(\mathbf{v} = \frac{1}{5}\begin{bmatrix} -6 \\ -1 \end{bmatrix} = \begin{bmatrix} -1.2 \\ -0.2 \end{bmatrix}\)A1 Correct velocity
Total: 3 marks
2(b)
AnswerMarks Guidance
\(v = \sqrt{1.2^2 + 0.2^2} = 1.22 \text{ ms}^{-1}\)M1 Finding speed from their velocity in part (a) (Must include addition of two terms)
A1FCorrect speed from their velocity. Accept 1.21
Total: 2 marks
**2(a)**
| $2\begin{bmatrix} 3 \\ -2 \end{bmatrix} + 3\begin{bmatrix} -4 \\ 1 \end{bmatrix} = 5\mathbf{v}$ | M1 | Three term vector equation, with a '+' sign, for conservation of momentum |
| | A1 | Correct equation. Deduct this first A mark for use of $mg$ |
| $\mathbf{v} = \frac{1}{5}\begin{bmatrix} -6 \\ -1 \end{bmatrix} = \begin{bmatrix} -1.2 \\ -0.2 \end{bmatrix}$ | A1 | Correct velocity |
| **Total: 3 marks** | | |

**2(b)**
| $v = \sqrt{1.2^2 + 0.2^2} = 1.22 \text{ ms}^{-1}$ | M1 | Finding speed from their velocity in part (a) (Must include addition of two terms) |
| | A1F | Correct speed from their velocity. Accept 1.21 |
| **Total: 2 marks** | | |
2 Two particles, $A$ and $B$, are moving on a smooth horizontal surface. Particle $A$ has mass 2 kg and velocity $\left[ \begin{array} { r } 3 \\ - 2 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$. Particle $B$ has mass 3 kg and velocity $\left[ \begin{array} { r } - 4 \\ 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$. The two particles collide, and they coalesce during the collision.
\begin{enumerate}[label=(\alph*)]
\item Find the velocity of the combined particles after the collision.
\item Find the speed of the combined particles after the collision.
\end{enumerate}

\hfill \mbox{\textit{AQA M1 2007 Q2 [5]}}