AQA S3 2006 June — Question 4 6 marks

Exam BoardAQA
ModuleS3 (Statistics 3)
Year2006
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Random Variables
TypeLinear combinations of independent variables
DifficultyModerate -0.3 This is a straightforward application of standard formulas for expectation and variance. Part (a) requires basic calculations from a probability distribution (E(R) = Σrp(r) and Var(R) = E(R²) - [E(R)]²). Part (b) applies linear combination formulas including the correlation term, which is A-level content but routine once the formulas are known. The calculations are mechanical with no problem-solving or conceptual challenges beyond formula recall.
Spec5.02b Expectation and variance: discrete random variables5.04b Linear combinations: of normal distributions

4 The table below shows the probability distribution for the number of students, \(R\), attending classes for a particular mathematics module.
\(\boldsymbol { r }\)678
\(\mathbf { P } ( \boldsymbol { R } = \boldsymbol { r } )\)0.10.60.3
  1. Find values for \(\mathrm { E } ( R )\) and \(\operatorname { Var } ( R )\).
  2. The number of students, \(S\), attending classes for a different mathematics module is such that $$\mathrm { E } ( S ) = 10.9 , \quad \operatorname { Var } ( S ) = 1.69 \quad \text { and } \quad \rho _ { R S } = \frac { 2 } { 3 }$$ Find values for the mean and variance of:
    1. \(T = R + S\);
    2. \(\quad D = S - R\).

Question 4:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(E(R) = (6 \times 0.1)+(7 \times 0.6)+(8 \times 0.3) = 0.6+4.2+2.4 = 7.2\)B1 CAO
\(E(R^2) = (3.6+29.4+19.2) = 52.2\)B1 CAO
\(\text{Var}(R) = E(R^2) - (E(R))^2\)M1 Use of formula
\(= 52.2 - 51.84 = 0.36\)A1 CAO
Part (b)(i)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(E(T) = 7.2 + 10.9 = 18.1\)B1\(\checkmark\) \(\checkmark\) on \(E(R)\)
\(\text{Cov}(R,S) = \rho_{RS} \times \sqrt{\text{Var}(R) \times \text{Var}(S)}\)M1 Use of; or equivalent. May be scored in (ii)
\(\text{Var}(T) = \text{Var}(R) + \text{Var}(S) + 2\text{Cov}(R,S)\)M1 Use of; or equivalent. May be scored in (ii)
\(= 0.36 + 1.69 + 2 \times \frac{2}{3}\sqrt{0.36 \times 1.69}\)
\(= 0.36 + 1.69 + 1.04 = 3.09\)A1 CAO
Part (b)(ii)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(E(D) = 10.9 - 7.2 = 3.7\)B1\(\checkmark\) \(\checkmark\) on \(E(R)\)
\(\text{Var}(D) = \text{Var}(S) + \text{Var}(R) - 2\text{Cov}(S,R)\)
\(= 1.69 + 0.36 - 2 \times \frac{2}{3}\sqrt{1.69 \times 0.36}\)
\(= 1.69 + 0.36 - 1.04 = 1.01\)B1 CAO
# Question 4:

## Part (a)

| Answer/Working | Marks | Guidance |
|---|---|---|
| $E(R) = (6 \times 0.1)+(7 \times 0.6)+(8 \times 0.3) = 0.6+4.2+2.4 = 7.2$ | B1 | CAO |
| $E(R^2) = (3.6+29.4+19.2) = 52.2$ | B1 | CAO |
| $\text{Var}(R) = E(R^2) - (E(R))^2$ | M1 | Use of formula |
| $= 52.2 - 51.84 = 0.36$ | A1 | CAO |

## Part (b)(i)

| Answer/Working | Marks | Guidance |
|---|---|---|
| $E(T) = 7.2 + 10.9 = 18.1$ | B1$\checkmark$ | $\checkmark$ on $E(R)$ |
| $\text{Cov}(R,S) = \rho_{RS} \times \sqrt{\text{Var}(R) \times \text{Var}(S)}$ | M1 | Use of; or equivalent. May be scored in (ii) |
| $\text{Var}(T) = \text{Var}(R) + \text{Var}(S) + 2\text{Cov}(R,S)$ | M1 | Use of; or equivalent. May be scored in (ii) |
| $= 0.36 + 1.69 + 2 \times \frac{2}{3}\sqrt{0.36 \times 1.69}$ | | |
| $= 0.36 + 1.69 + 1.04 = 3.09$ | A1 | CAO |

## Part (b)(ii)

| Answer/Working | Marks | Guidance |
|---|---|---|
| $E(D) = 10.9 - 7.2 = 3.7$ | B1$\checkmark$ | $\checkmark$ on $E(R)$ |
| $\text{Var}(D) = \text{Var}(S) + \text{Var}(R) - 2\text{Cov}(S,R)$ | | |
| $= 1.69 + 0.36 - 2 \times \frac{2}{3}\sqrt{1.69 \times 0.36}$ | | |
| $= 1.69 + 0.36 - 1.04 = 1.01$ | B1 | CAO |
4 The table below shows the probability distribution for the number of students, $R$, attending classes for a particular mathematics module.

\begin{center}
\begin{tabular}{ | c | c | c | c | }
\hline
$\boldsymbol { r }$ & 6 & 7 & 8 \\
\hline
$\mathbf { P } ( \boldsymbol { R } = \boldsymbol { r } )$ & 0.1 & 0.6 & 0.3 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Find values for $\mathrm { E } ( R )$ and $\operatorname { Var } ( R )$.
\item The number of students, $S$, attending classes for a different mathematics module is such that

$$\mathrm { E } ( S ) = 10.9 , \quad \operatorname { Var } ( S ) = 1.69 \quad \text { and } \quad \rho _ { R S } = \frac { 2 } { 3 }$$

Find values for the mean and variance of:
\begin{enumerate}[label=(\roman*)]
\item $T = R + S$;
\item $\quad D = S - R$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA S3 2006 Q4 [6]}}