AQA C4 2006 June — Question 1 8 marks

Exam BoardAQA
ModuleC4 (Core Mathematics 4)
Year2006
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolynomial Division & Manipulation
TypeSimple Algebraic Fraction Simplification
DifficultyModerate -0.3 This is a standard C4 polynomial question requiring routine application of the Factor Theorem, polynomial division, and algebraic fraction simplification. While multi-part, each step follows predictable textbook methods with no novel problem-solving required, making it slightly easier than average.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02k Simplify rational expressions: factorising, cancelling, algebraic division

1
  1. The polynomial \(\mathrm { p } ( x )\) is defined by \(\mathrm { p } ( x ) = 6 x ^ { 3 } - 19 x ^ { 2 } + 9 x + 10\).
    1. Find \(\mathrm { p } ( 2 )\).
    2. Use the Factor Theorem to show that ( \(2 x + 1\) ) is a factor of \(\mathrm { p } ( x )\).
    3. Write \(\mathrm { p } ( x )\) as the product of three linear factors.
  2. Hence simplify \(\frac { 3 x ^ { 2 } - 6 x } { 6 x ^ { 3 } - 19 x ^ { 2 } + 9 x + 10 }\).

1
\begin{enumerate}[label=(\alph*)]
\item The polynomial $\mathrm { p } ( x )$ is defined by $\mathrm { p } ( x ) = 6 x ^ { 3 } - 19 x ^ { 2 } + 9 x + 10$.
\begin{enumerate}[label=(\roman*)]
\item Find $\mathrm { p } ( 2 )$.
\item Use the Factor Theorem to show that ( $2 x + 1$ ) is a factor of $\mathrm { p } ( x )$.
\item Write $\mathrm { p } ( x )$ as the product of three linear factors.
\end{enumerate}\item Hence simplify $\frac { 3 x ^ { 2 } - 6 x } { 6 x ^ { 3 } - 19 x ^ { 2 } + 9 x + 10 }$.
\end{enumerate}

\hfill \mbox{\textit{AQA C4 2006 Q1 [8]}}