Edexcel C3 — Question 7 11 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks11
PaperDownload PDF ↗
TopicExponential Functions
TypeLogistic growth model
DifficultyStandard +0.8 This logistic growth question requires multiple algebraic manipulations including exponential equations, logarithms, and limit analysis. While part (a) is routine substitution, parts (b-d) demand understanding of exponential manipulation, solving transcendental equations, and proving a population bound through algebraic rearrangement and limit behavior—significantly more sophisticated than standard C3 exponential questions.
Spec1.06g Equations with exponentials: solve a^x = b1.06i Exponential growth/decay: in modelling context

7. A particular species of orchid is being studied. The population \(p\) at time \(t\) years after the study started is assumed to be $$p = \frac { 2800 a \mathrm { e } ^ { 0.2 t } } { 1 + a \mathrm { e } ^ { 0.2 t } } , \text { where } a \text { is a constant. }$$ Given that there were 300 orchids when the study started,
  1. show that \(a = 0.12\),
  2. use the equation with \(a = 0.12\) to predict the number of years before the population of orchids reaches 1850 .
  3. Show that \(p = \frac { 336 } { 0.12 + \mathrm { e } ^ { - 0.2 t } }\).
  4. Hence show that the population cannot exceed 2800.

7. A particular species of orchid is being studied. The population $p$ at time $t$ years after the study started is assumed to be

$$p = \frac { 2800 a \mathrm { e } ^ { 0.2 t } } { 1 + a \mathrm { e } ^ { 0.2 t } } , \text { where } a \text { is a constant. }$$

Given that there were 300 orchids when the study started,
\begin{enumerate}[label=(\alph*)]
\item show that $a = 0.12$,
\item use the equation with $a = 0.12$ to predict the number of years before the population of orchids reaches 1850 .
\item Show that $p = \frac { 336 } { 0.12 + \mathrm { e } ^ { - 0.2 t } }$.
\item Hence show that the population cannot exceed 2800.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q7 [11]}}