OCR H240/02 2018 September — Question 7 7 marks

Exam BoardOCR
ModuleH240/02 (Pure Mathematics and Statistics)
Year2018
SessionSeptember
Marks7
TopicNumerical integration
TypeLimit of rectangle sum equals integral
DifficultyStandard +0.3 This is a structured multi-part question on Riemann sums that guides students through each step: writing the sum, applying a given identity, and taking a limit. While it involves algebraic manipulation and understanding the limiting process, the question provides the key identity and clear scaffolding, making it slightly easier than average for A-level.
Spec1.04g Sigma notation: for sums of series1.08g Integration as limit of sum: Riemann sums

7 The diagram shows part of the curve \(y = x ^ { 2 }\) for \(0 \leqslant x \leqslant p\), where \(p\) is a constant. \includegraphics[max width=\textwidth, alt={}, center]{85de9a39-f8be-40ee-b0c8-e2e632be93d8-5_736_543_669_762} The area \(A\) of the region enclosed by the curve, the \(x\)-axis and the line \(x = p\) is given approximately by the sum \(S\) of the areas of \(n\) rectangles, each of width \(h\), where \(h\) is small and \(n h = p\). The first three such rectangles are shown in the diagram.
  1. Find an expression for \(S\) in terms of \(n\) and \(h\).
  2. Use the identity \(\sum _ { r = 1 } ^ { n } r ^ { 2 } \equiv \frac { 1 } { 6 } n ( n + 1 ) ( 2 n + 1 )\) to show that \(S = \frac { 1 } { 6 } p ( p + h ) ( 2 p + h )\).
  3. Show how to use this result to find \(A\) in terms of \(p\).

7 The diagram shows part of the curve $y = x ^ { 2 }$ for $0 \leqslant x \leqslant p$, where $p$ is a constant.\\
\includegraphics[max width=\textwidth, alt={}, center]{85de9a39-f8be-40ee-b0c8-e2e632be93d8-5_736_543_669_762}

The area $A$ of the region enclosed by the curve, the $x$-axis and the line $x = p$ is given approximately by the sum $S$ of the areas of $n$ rectangles, each of width $h$, where $h$ is small and $n h = p$. The first three such rectangles are shown in the diagram.\\
(i) Find an expression for $S$ in terms of $n$ and $h$.\\
(ii) Use the identity $\sum _ { r = 1 } ^ { n } r ^ { 2 } \equiv \frac { 1 } { 6 } n ( n + 1 ) ( 2 n + 1 )$ to show that $S = \frac { 1 } { 6 } p ( p + h ) ( 2 p + h )$.\\
(iii) Show how to use this result to find $A$ in terms of $p$.

\hfill \mbox{\textit{OCR H240/02 2018 Q7 [7]}}