OCR FP1 AS 2018 March — Question 3 6 marks

Exam BoardOCR
ModuleFP1 AS (Further Pure 1 AS)
Year2018
SessionMarch
Marks6
TopicVectors: Lines & Planes
TypeLine intersection with line
DifficultyStandard +0.3 This is a standard two-part question on line intersection requiring students to equate vector equations and solve simultaneous equations for parameters λ and μ, then use the result to find the unknown constant a. While it involves multiple steps and algebraic manipulation, it follows a routine procedure taught in FP1 with no novel insight required, making it slightly easier than average.
Spec4.04e Line intersections: parallel, skew, or intersecting

$$\begin{aligned} l _ { 1 } : \mathbf { r } = \left( \begin{array} { c } 4 \\ 2 \\ 5 \end{array} \right) + \lambda \left( \begin{array} { c } 1 \\ 3 \\ - 2 \end{array} \right) \\ & l _ { 2 } : \mathbf { r } = \left( \begin{array} { l } 1 \\ a \\ 1 \end{array} \right) + \mu \left( \begin{array} { c } 2 \\ 2 \\ - 3 \end{array} \right) \end{aligned}$$
  1. Find the position vector of the point of intersection of \(l _ { 1 }\) and \(l _ { 2 }\).
  2. Determine the value of \(a\).

AnswerMarks Guidance
(i) \(3 + \lambda = 1 + 2\mu\) and \(-5 - 2\lambda = 1 - 3\mu\)M1 Attempt to solve simultaneously (eg adding or subtracting two equations even if incorrect)
eg \(6 + 2\lambda = 2 + 4\mu\) and or \(6 + 2\lambda - 5 - 2\lambda = 2 + 4\mu + 1 - 3\mu\)M1
\(\lambda = -6\)A1
\(\begin{pmatrix} -3 \\ -15 \\ 7 \end{pmatrix}\)A1 Condone as coordinates
[4]
(ii) \(a + 2\mu = -15\) and \(\mu = -2\)M1 Must be seen in (ii)
\(-11\)A1
[2]
**(i)** $3 + \lambda = 1 + 2\mu$ and $-5 - 2\lambda = 1 - 3\mu$ | M1 | Attempt to solve simultaneously (eg adding or subtracting two equations even if incorrect)

eg $6 + 2\lambda = 2 + 4\mu$ and or $6 + 2\lambda - 5 - 2\lambda = 2 + 4\mu + 1 - 3\mu$ | M1 | 

$\lambda = -6$ | A1 | 

$\begin{pmatrix} -3 \\ -15 \\ 7 \end{pmatrix}$ | A1 | Condone as coordinates

| [4] |

**(ii)** $a + 2\mu = -15$ and $\mu = -2$ | M1 | Must be seen in (ii)

$-11$ | A1 | 

| [2] |

---
$$\begin{aligned}
l _ { 1 } : \mathbf { r } = \left( \begin{array} { c } 
4 \\
2 \\
5
\end{array} \right) + \lambda \left( \begin{array} { c } 
1 \\
3 \\
- 2
\end{array} \right) \\
& l _ { 2 } : \mathbf { r } = \left( \begin{array} { l } 
1 \\
a \\
1
\end{array} \right) + \mu \left( \begin{array} { c } 
2 \\
2 \\
- 3
\end{array} \right)
\end{aligned}$$

(i) Find the position vector of the point of intersection of $l _ { 1 }$ and $l _ { 2 }$.\\
(ii) Determine the value of $a$.

\hfill \mbox{\textit{OCR FP1 AS 2018 Q3 [6]}}