OCR Further Statistics 2018 March — Question 6 10 marks

Exam BoardOCR
ModuleFurther Statistics (Further Statistics)
Year2018
SessionMarch
Marks10
TopicChi-squared test of independence
TypeInterpret association after test
DifficultyStandard +0.3 This is a straightforward chi-squared test of independence with a 2×3 contingency table. Students need to calculate expected frequencies, compute the test statistic, compare to critical value, and identify the largest contribution. While it requires multiple steps, it's a standard textbook application with no novel insight required, making it slightly easier than average for Further Maths statistics.
Spec5.06a Chi-squared: contingency tables

6 The captain of a sports team analyses the team's results according to the weather conditions, classified as "sunny" and "not sunny". The frequencies are shown in the following table.
\cline { 3 - 5 } \multicolumn{2}{c|}{}Results
\cline { 3 - 5 } \multicolumn{2}{c|}{}WinDrawLose
\multirow{2}{*}{Weather}Sunny1235
\cline { 2 - 5 }Not sunny81210
  1. Test at the \(5 \%\) significance level whether the team's performances are associated with weather conditions.
  2. (a) Identify the cell that gives the largest contribution to the test statistic.
    (b) Interpret your answer to part (ii)(a).

Part (i)
\(H_0\): no association between weather and results, \(H_1\): association
AnswerMarks Guidance
Expected frequenciesM1 Find expected frequencies
A1
86 6
129 9
M1Use \(\Sigma(O - E)^2/E\)
\(\chi^2 = 2 + 1.5 + 0.167 + 1.333 + 1 + 0.111\)A1 Awrt 6.11
\(= 6.111\)A1 Compare with 5.991, needs M1M1
\(6.111 > 5.991\)M1ft ft on 6.111 only
Reject \(H_0\). Significance evidence of association between results and weatherA1ft Contextualised, not too definite
Part (ii)(a)
AnswerMarks Guidance
Sunny/WinB1 FT on \(\chi^2\) if M1M1 and evidence
Part (ii)(b)
AnswerMarks Guidance
The team wins more than average in sunny conditionsB1 Or equivalent
## Part (i)
$H_0$: no association between weather and results, $H_1$: association

Expected frequencies | M1 | Find expected frequencies
| A1 |

| 8 | 6 | 6 |
|---|---|---|
| 12 | 9 | 9 |

| M1 | Use $\Sigma(O - E)^2/E$
$\chi^2 = 2 + 1.5 + 0.167 + 1.333 + 1 + 0.111$ | A1 | Awrt 6.11
$= 6.111$ | A1 | Compare with 5.991, needs M1M1
$6.111 > 5.991$ | M1ft | ft on 6.111 only
Reject $H_0$. Significance evidence of association between results and weather | A1ft | Contextualised, not too definite

## Part (ii)(a)
Sunny/Win | B1 | FT on $\chi^2$ if M1M1 and evidence

## Part (ii)(b)
The team wins more than average in sunny conditions | B1 | Or equivalent | FT from part (a)
6 The captain of a sports team analyses the team's results according to the weather conditions, classified as "sunny" and "not sunny". The frequencies are shown in the following table.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\cline { 3 - 5 }
\multicolumn{2}{c|}{} & \multicolumn{3}{c|}{Results} \\
\cline { 3 - 5 }
\multicolumn{2}{c|}{} & Win & Draw & Lose \\
\hline
\multirow{2}{*}{Weather} & Sunny & 12 & 3 & 5 \\
\cline { 2 - 5 }
 & Not sunny & 8 & 12 & 10 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\roman*)]
\item Test at the $5 \%$ significance level whether the team's performances are associated with weather conditions.
\item (a) Identify the cell that gives the largest contribution to the test statistic.\\
(b) Interpret your answer to part (ii)(a).
\end{enumerate}

\hfill \mbox{\textit{OCR Further Statistics 2018 Q6 [10]}}