| Exam Board | CAIE |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2020 |
| Session | November |
| Marks | 3 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions |
| Type | Direct collision, find final speed |
| Difficulty | Easy -1.3 This is a straightforward application of conservation of momentum with given values requiring only substitution into the standard formula. The question explicitly provides all necessary information and requires minimal problem-solving—just recall the momentum formula (part a) and apply conservation of momentum in one equation (part b). |
| Spec | 6.03a Linear momentum: p = mv6.03b Conservation of momentum: 1D two particles |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Momentum \(= 0.2 \times 2 = 0.4\) kg ms\(^{-1}\) | B1 | |
| Total: 1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(0.4 = 0.2 \times 0.3 + 0.5v\) | M1 | Apply conservation of momentum, 3 terms |
| \(v = 0.68\) ms\(^{-1}\) | A1 FT | FT on answer in 1(a) |
| Total: 2 |
**Question 1:**
**Part (a):**
| Answer | Mark | Guidance |
|--------|------|----------|
| Momentum $= 0.2 \times 2 = 0.4$ kg ms$^{-1}$ | B1 | |
| | **Total: 1** | |
**Part (b):**
| Answer | Mark | Guidance |
|--------|------|----------|
| $0.4 = 0.2 \times 0.3 + 0.5v$ | M1 | Apply conservation of momentum, 3 terms |
| $v = 0.68$ ms$^{-1}$ | A1 FT | FT on answer in 1(a) |
| | **Total: 2** | |
---1 Two particles $P$ and $Q$, of masses 0.2 kg and 0.5 kg respectively, are at rest on a smooth horizontal plane. $P$ is projected towards $Q$ with speed $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Write down the momentum of $P$.
\item After the collision $P$ continues to move in the same direction with speed $0.3 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
Find the speed of $Q$ after the collision.
\end{enumerate}
\hfill \mbox{\textit{CAIE M1 2020 Q1 [3]}}