CAIE P1 2020 Specimen — Question 2 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2020
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeSolve equation with inverses
DifficultyModerate -0.8 This is a straightforward P1 question requiring students to find the inverse of f, set it equal to g(x), and solve a linear equation. It involves only basic algebraic manipulation with no conceptual challenges beyond recalling the inverse function procedure.
Spec1.02v Inverse and composite functions: graphs and conditions for existence

2 Functions \(f\) and \(g\) are defined by $$\begin{aligned} \mathrm { f } : x & \mapsto 3 x + 2 , \quad x \in \mathbb { R } , \\ \mathrm {~g} : x & \mapsto 4 x - 12 , \quad x \in \mathbb { R } . \end{aligned}$$ Solve the equation \(\mathrm { f } ^ { - 1 } ( x ) = \mathrm { gf } ( x )\).

Question 2:
AnswerMarks Guidance
AnswerMarks Guidance
\(f^{-1}(x) = \frac{x-2}{3}\)1 B1
\(gf(x) = 4(3x+2) - 12\)1 B1
Equate \(f^{-1}(x)\) and \(gf(x)\) expressions, \(x = \frac{2}{7}\)2 M1A1
Total4
## Question 2:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $f^{-1}(x) = \frac{x-2}{3}$ | 1 B1 | |
| $gf(x) = 4(3x+2) - 12$ | 1 B1 | |
| Equate $f^{-1}(x)$ and $gf(x)$ expressions, $x = \frac{2}{7}$ | 2 M1A1 | |
| **Total** | **4** | |
2 Functions $f$ and $g$ are defined by

$$\begin{aligned}
\mathrm { f } : x & \mapsto 3 x + 2 , \quad x \in \mathbb { R } , \\
\mathrm {~g} : x & \mapsto 4 x - 12 , \quad x \in \mathbb { R } .
\end{aligned}$$

Solve the equation $\mathrm { f } ^ { - 1 } ( x ) = \mathrm { gf } ( x )$.\\

\hfill \mbox{\textit{CAIE P1 2020 Q2 [4]}}