OCR H240/03 2018 June — Question 3 6 marks

Exam BoardOCR
ModuleH240/03 (Pure Mathematics and Mechanics)
Year2018
SessionJune
Marks6
PaperDownload PDF ↗
TopicInequalities
TypePerimeter or area constraint inequality
DifficultyModerate -0.3 This is a straightforward inequality problem requiring students to translate verbal constraints into algebraic inequalities (x+3 ≥ 14.5 and x(x+3) < 180), then solve a quadratic inequality. While it involves multiple steps and a quadratic, the setup is routine and the solving techniques are standard A-level fare, making it slightly easier than average.
Spec1.02g Inequalities: linear and quadratic in single variable

3 In this question you must show detailed reasoning. A gardener is planning the design for a rectangular flower bed. The requirements are:
  • the length of the flower bed is to be 3 m longer than the width,
  • the length of the flower bed must be at least 14.5 m ,
  • the area of the flower bed must be less than \(180 \mathrm {~m} ^ { 2 }\).
The width of the flower bed is \(x \mathrm {~m}\).
By writing down and solving appropriate inequalities in \(x\), determine the set of possible values for the width of the flower bed.

Question 3:
DR
AnswerMarks Guidance
\(x + 3 \geq 14.5\)M1 3.1b Accept any inequality or equals and any letter for the width
\(x \geq 11.5\)A1 1.1 Correct inequality (seen or implied); M1A1 correct answer with no working
\(x(x+3) < 180\)M1 3.1b Accept any inequality or equals
\(x^2 + 3x - 180 (< 0) \Rightarrow (x-12)(x+15)(< 0)\)M1 1.1 Correct expansion and attempt to solve three-term quadratic; SC B1: \(x < \sqrt{60}\)
\(-15 < x < 12\)A1 1.1 Correct inequalities (seen or implied); B1: \(x \geq 29/6\)
\(11.5 \leq x < 12\)B1 1.1 [6]
## Question 3:

**DR**

$x + 3 \geq 14.5$ | M1 3.1b | Accept any inequality or equals and any letter for the width

$x \geq 11.5$ | A1 1.1 | Correct inequality (seen or implied); M1A1 correct answer with no working

$x(x+3) < 180$ | M1 3.1b | Accept any inequality or equals

$x^2 + 3x - 180 (< 0) \Rightarrow (x-12)(x+15)(< 0)$ | M1 1.1 | Correct expansion and attempt to solve three-term quadratic; **SC** B1: $x < \sqrt{60}$

$-15 < x < 12$ | A1 1.1 | Correct inequalities (seen or implied); B1: $x \geq 29/6$

$11.5 \leq x < 12$ | B1 1.1 [6] | —

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3 In this question you must show detailed reasoning.
A gardener is planning the design for a rectangular flower bed. The requirements are:

\begin{itemize}
  \item the length of the flower bed is to be 3 m longer than the width,
  \item the length of the flower bed must be at least 14.5 m ,
  \item the area of the flower bed must be less than $180 \mathrm {~m} ^ { 2 }$.
\end{itemize}

The width of the flower bed is $x \mathrm {~m}$.\\
By writing down and solving appropriate inequalities in $x$, determine the set of possible values for the width of the flower bed.

\hfill \mbox{\textit{OCR H240/03 2018 Q3 [6]}}