Edexcel FD2 2023 June — Question 3 9 marks

Exam BoardEdexcel
ModuleFD2 (Further Decision 2)
Year2023
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNetwork Flows
TypeTransportation LP formulation
DifficultyStandard +0.3 This is a standard textbook transportation problem requiring routine application of well-defined algorithms (north-west corner, stepping-stone method). While it involves multiple steps and careful bookkeeping, it requires no problem-solving insight—students simply follow mechanical procedures taught in FD2. The LP formulation in part (a) is straightforward constraint writing. This is easier than average A-level maths because it's purely algorithmic with no conceptual challenge.
Spec7.06a LP formulation: variables, constraints, objective function7.06b Slack variables: converting inequalities to equations7.06c Working with constraints: algebra and ad hoc methods

3. The table below shows the stock held at each supply point and the stock required at each demand point in a standard transportation problem. The table also shows the cost, in pounds, of transporting the stock from each supply point to each demand point.
\cline { 2 - 5 } \multicolumn{1}{c|}{}QRSSupply
A23181245
B8101427
C11142134
D19151150
Demand753744
The problem is partially described by the linear programming formulation below.
Let \(x _ { i j }\) be the number of units transported from i to j $$\begin{aligned} & \text { where } \quad i \in \{ A , B , C , D \} \\ & \quad j \in \{ Q , R , S \} \text { and } x _ { i j } \geqslant 0 \\ & \text { Minimise } P = 23 x _ { A Q } + 18 x _ { A R } + 12 x _ { A S } + 8 x _ { B Q } + 10 x _ { B R } + 14 x _ { B S } \\ & \quad + 11 x _ { C Q } + 14 x _ { C R } + 21 x _ { C S } + 19 x _ { D Q } + 15 x _ { D R } + 11 x _ { D S } \end{aligned}$$
  1. Write down, as inequalities, the constraints of the linear program.
  2. Use the north-west corner method to obtain an initial solution to this transportation problem.
  3. Taking AS as the entering cell, use the stepping-stone method to find an improved solution. Make your route clear.
  4. Perform one further iteration of the stepping-stone method to obtain an improved solution. You must make your method clear by showing the route and the

Question 3:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\sum x_{Aj} \leq 45\), \(\sum x_{Bj} \leq 27\), \(\sum x_{Cj} \leq 34\), \(\sum x_{Dj} \leq 50\)M1 At least five equations or inequalities with unit coefficients (at least 3 correct)
\(\sum x_{iQ} \geq 75\), \(\sum x_{iR} \geq 37\), \(\sum x_{iS} \geq 44\)A1 CAO must be inequalities – check signs and notation carefully
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
North-west corner solution: A-Q=45, B-Q=27, C-Q=3, C-R=31, D-R=6, D-S=44B1 CAO for north-west corner method
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Stepping stone route with \(\theta\): \(A\): Q=\(45-\theta\), S=\(\theta\); B: Q=27; C: Q=\(3+\theta\), R=\(31-\theta\); D: R=\(6+\theta\), S=\(44-\theta\)M1 A valid route shown, AS chosen as entering cell, only one empty square used, \(\theta\)s balance
Giving: A=14, S=31; B=27; C=34; D: R=37, S=13A1 CAO (with no zero in cell CR)
Part (d):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Shadow costs and improvement indices found: rows 23, 8, 11, 22; columns 0, \(-7\), \(-11\); improvement indices for empty cells including \(-15\), \(-12\), \(-1\), \(0\)M1 Finding 7 shadow costs and 6 improvement indices
Shadow costs CAO (Alternative: columns 0, \(-7\), \(-11\); rows 23, 8, 11, 22)A1 CAO
New \(\theta\) route: A: Q=\(14-\theta\), S=\(31+\theta\); D: Q=\(\theta\), S=\(13-\theta\)M1 A valid route shown, most negative II chosen, only one empty square used, \(\theta\)s balance
Giving: A=1, S=44; B=27; C=34; D: Q=13, R=37. Entering cell is DQ and exiting cell is DSA1 cao – including the deduction of both entering and exiting cells
## Question 3:

### Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sum x_{Aj} \leq 45$, $\sum x_{Bj} \leq 27$, $\sum x_{Cj} \leq 34$, $\sum x_{Dj} \leq 50$ | M1 | At least five equations or inequalities with unit coefficients (at least 3 correct) |
| $\sum x_{iQ} \geq 75$, $\sum x_{iR} \geq 37$, $\sum x_{iS} \geq 44$ | A1 | CAO must be inequalities – check signs and notation carefully |

### Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| North-west corner solution: A-Q=45, B-Q=27, C-Q=3, C-R=31, D-R=6, D-S=44 | B1 | CAO for north-west corner method |

### Part (c):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Stepping stone route with $\theta$: $A$: Q=$45-\theta$, S=$\theta$; B: Q=27; C: Q=$3+\theta$, R=$31-\theta$; D: R=$6+\theta$, S=$44-\theta$ | M1 | A valid route shown, AS chosen as entering cell, only one empty square used, $\theta$s balance |
| Giving: A=14, S=31; B=27; C=34; D: R=37, S=13 | A1 | CAO (with no zero in cell CR) |

### Part (d):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Shadow costs and improvement indices found: rows 23, 8, 11, 22; columns 0, $-7$, $-11$; improvement indices for empty cells including $-15$, $-12$, $-1$, $0$ | M1 | Finding 7 shadow costs and 6 improvement indices |
| Shadow costs CAO (Alternative: columns 0, $-7$, $-11$; rows 23, 8, 11, 22) | A1 | CAO |
| New $\theta$ route: A: Q=$14-\theta$, S=$31+\theta$; D: Q=$\theta$, S=$13-\theta$ | M1 | A valid route shown, most negative II chosen, only one empty square used, $\theta$s balance |
| Giving: A=1, S=44; B=27; C=34; D: Q=13, R=37. Entering cell is DQ and exiting cell is DS | A1 | cao – including the deduction of both entering and exiting cells |

---
3. The table below shows the stock held at each supply point and the stock required at each demand point in a standard transportation problem. The table also shows the cost, in pounds, of transporting the stock from each supply point to each demand point.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\cline { 2 - 5 }
\multicolumn{1}{c|}{} & Q & R & S & Supply \\
\hline
A & 23 & 18 & 12 & 45 \\
\hline
B & 8 & 10 & 14 & 27 \\
\hline
C & 11 & 14 & 21 & 34 \\
\hline
D & 19 & 15 & 11 & 50 \\
\hline
Demand & 75 & 37 & 44 &  \\
\hline
\end{tabular}
\end{center}

The problem is partially described by the linear programming formulation below.\\
Let $x _ { i j }$ be the number of units transported from i to j

$$\begin{aligned}
& \text { where } \quad i \in \{ A , B , C , D \} \\
& \quad j \in \{ Q , R , S \} \text { and } x _ { i j } \geqslant 0 \\
& \text { Minimise } P = 23 x _ { A Q } + 18 x _ { A R } + 12 x _ { A S } + 8 x _ { B Q } + 10 x _ { B R } + 14 x _ { B S } \\
& \quad + 11 x _ { C Q } + 14 x _ { C R } + 21 x _ { C S } + 19 x _ { D Q } + 15 x _ { D R } + 11 x _ { D S }
\end{aligned}$$
\begin{enumerate}[label=(\alph*)]
\item Write down, as inequalities, the constraints of the linear program.
\item Use the north-west corner method to obtain an initial solution to this transportation problem.
\item Taking AS as the entering cell, use the stepping-stone method to find an improved solution. Make your route clear.
\item Perform one further iteration of the stepping-stone method to obtain an improved solution. You must make your method clear by showing the route and the

\begin{itemize}
  \item shadow costs
  \item improvement indices
  \item entering cell and exiting cell
\end{itemize}
\end{enumerate}

\hfill \mbox{\textit{Edexcel FD2 2023 Q3 [9]}}