| Exam Board | Edexcel |
|---|---|
| Module | FD2 (Further Decision 2) |
| Year | 2023 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Network Flows |
| Type | Transportation LP formulation |
| Difficulty | Standard +0.3 This is a standard textbook transportation problem requiring routine application of well-defined algorithms (north-west corner, stepping-stone method). While it involves multiple steps and careful bookkeeping, it requires no problem-solving insight—students simply follow mechanical procedures taught in FD2. The LP formulation in part (a) is straightforward constraint writing. This is easier than average A-level maths because it's purely algorithmic with no conceptual challenge. |
| Spec | 7.06a LP formulation: variables, constraints, objective function7.06b Slack variables: converting inequalities to equations7.06c Working with constraints: algebra and ad hoc methods |
| \cline { 2 - 5 } \multicolumn{1}{c|}{} | Q | R | S | Supply |
| A | 23 | 18 | 12 | 45 |
| B | 8 | 10 | 14 | 27 |
| C | 11 | 14 | 21 | 34 |
| D | 19 | 15 | 11 | 50 |
| Demand | 75 | 37 | 44 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\sum x_{Aj} \leq 45\), \(\sum x_{Bj} \leq 27\), \(\sum x_{Cj} \leq 34\), \(\sum x_{Dj} \leq 50\) | M1 | At least five equations or inequalities with unit coefficients (at least 3 correct) |
| \(\sum x_{iQ} \geq 75\), \(\sum x_{iR} \geq 37\), \(\sum x_{iS} \geq 44\) | A1 | CAO must be inequalities – check signs and notation carefully |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| North-west corner solution: A-Q=45, B-Q=27, C-Q=3, C-R=31, D-R=6, D-S=44 | B1 | CAO for north-west corner method |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Stepping stone route with \(\theta\): \(A\): Q=\(45-\theta\), S=\(\theta\); B: Q=27; C: Q=\(3+\theta\), R=\(31-\theta\); D: R=\(6+\theta\), S=\(44-\theta\) | M1 | A valid route shown, AS chosen as entering cell, only one empty square used, \(\theta\)s balance |
| Giving: A=14, S=31; B=27; C=34; D: R=37, S=13 | A1 | CAO (with no zero in cell CR) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Shadow costs and improvement indices found: rows 23, 8, 11, 22; columns 0, \(-7\), \(-11\); improvement indices for empty cells including \(-15\), \(-12\), \(-1\), \(0\) | M1 | Finding 7 shadow costs and 6 improvement indices |
| Shadow costs CAO (Alternative: columns 0, \(-7\), \(-11\); rows 23, 8, 11, 22) | A1 | CAO |
| New \(\theta\) route: A: Q=\(14-\theta\), S=\(31+\theta\); D: Q=\(\theta\), S=\(13-\theta\) | M1 | A valid route shown, most negative II chosen, only one empty square used, \(\theta\)s balance |
| Giving: A=1, S=44; B=27; C=34; D: Q=13, R=37. Entering cell is DQ and exiting cell is DS | A1 | cao – including the deduction of both entering and exiting cells |
## Question 3:
### Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sum x_{Aj} \leq 45$, $\sum x_{Bj} \leq 27$, $\sum x_{Cj} \leq 34$, $\sum x_{Dj} \leq 50$ | M1 | At least five equations or inequalities with unit coefficients (at least 3 correct) |
| $\sum x_{iQ} \geq 75$, $\sum x_{iR} \geq 37$, $\sum x_{iS} \geq 44$ | A1 | CAO must be inequalities – check signs and notation carefully |
### Part (b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| North-west corner solution: A-Q=45, B-Q=27, C-Q=3, C-R=31, D-R=6, D-S=44 | B1 | CAO for north-west corner method |
### Part (c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Stepping stone route with $\theta$: $A$: Q=$45-\theta$, S=$\theta$; B: Q=27; C: Q=$3+\theta$, R=$31-\theta$; D: R=$6+\theta$, S=$44-\theta$ | M1 | A valid route shown, AS chosen as entering cell, only one empty square used, $\theta$s balance |
| Giving: A=14, S=31; B=27; C=34; D: R=37, S=13 | A1 | CAO (with no zero in cell CR) |
### Part (d):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Shadow costs and improvement indices found: rows 23, 8, 11, 22; columns 0, $-7$, $-11$; improvement indices for empty cells including $-15$, $-12$, $-1$, $0$ | M1 | Finding 7 shadow costs and 6 improvement indices |
| Shadow costs CAO (Alternative: columns 0, $-7$, $-11$; rows 23, 8, 11, 22) | A1 | CAO |
| New $\theta$ route: A: Q=$14-\theta$, S=$31+\theta$; D: Q=$\theta$, S=$13-\theta$ | M1 | A valid route shown, most negative II chosen, only one empty square used, $\theta$s balance |
| Giving: A=1, S=44; B=27; C=34; D: Q=13, R=37. Entering cell is DQ and exiting cell is DS | A1 | cao – including the deduction of both entering and exiting cells |
---
3. The table below shows the stock held at each supply point and the stock required at each demand point in a standard transportation problem. The table also shows the cost, in pounds, of transporting the stock from each supply point to each demand point.
\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\cline { 2 - 5 }
\multicolumn{1}{c|}{} & Q & R & S & Supply \\
\hline
A & 23 & 18 & 12 & 45 \\
\hline
B & 8 & 10 & 14 & 27 \\
\hline
C & 11 & 14 & 21 & 34 \\
\hline
D & 19 & 15 & 11 & 50 \\
\hline
Demand & 75 & 37 & 44 & \\
\hline
\end{tabular}
\end{center}
The problem is partially described by the linear programming formulation below.\\
Let $x _ { i j }$ be the number of units transported from i to j
$$\begin{aligned}
& \text { where } \quad i \in \{ A , B , C , D \} \\
& \quad j \in \{ Q , R , S \} \text { and } x _ { i j } \geqslant 0 \\
& \text { Minimise } P = 23 x _ { A Q } + 18 x _ { A R } + 12 x _ { A S } + 8 x _ { B Q } + 10 x _ { B R } + 14 x _ { B S } \\
& \quad + 11 x _ { C Q } + 14 x _ { C R } + 21 x _ { C S } + 19 x _ { D Q } + 15 x _ { D R } + 11 x _ { D S }
\end{aligned}$$
\begin{enumerate}[label=(\alph*)]
\item Write down, as inequalities, the constraints of the linear program.
\item Use the north-west corner method to obtain an initial solution to this transportation problem.
\item Taking AS as the entering cell, use the stepping-stone method to find an improved solution. Make your route clear.
\item Perform one further iteration of the stepping-stone method to obtain an improved solution. You must make your method clear by showing the route and the
\begin{itemize}
\item shadow costs
\item improvement indices
\item entering cell and exiting cell
\end{itemize}
\end{enumerate}
\hfill \mbox{\textit{Edexcel FD2 2023 Q3 [9]}}