Edexcel FP2 2019 June — Question 1 5 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2019
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeCircle of Apollonius locus
DifficultyStandard +0.3 This is a standard Further Maths locus question requiring algebraic manipulation of modulus conditions. Part (a) involves routine expansion and simplification of |z-3|=4|z+1| to reach a circle equation, while part (b) requires geometric interpretation to find the maximum distance from origin. The techniques are well-practiced in FP2 with no novel insight required, making it slightly easier than average.
Spec4.02k Argand diagrams: geometric interpretation4.02o Loci in Argand diagram: circles, half-lines

  1. A complex number \(z = x + \mathrm { i } y\) is represented by the point \(P\) in an Argand diagram.
Given that $$| z - 3 | = 4 | z + 1 |$$
  1. show that the locus of \(P\) has equation $$15 x ^ { 2 } + 15 y ^ { 2 } + 38 x + 7 = 0$$
  2. Hence find the maximum value of \(| z |\)

Question 1 (Eigenvalues/Eigenvectors):
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Attempts to expand determinant to find characteristic polynomialM1 Other expansion methods possible
Correct expansion (need not be simplified, need not equal zero)A1 Allow recovery of missing brackets if indicated by later working
Attempts to take out factor of \((\lambda - 2)\)M1 May first expand to cubic or spot factor
\((6-\lambda)\big((3-\lambda)^2-1\big)+2\big(2(\lambda-3)+2\big)+2\big(2-2(3-\lambda)\big)=(6-\lambda)(4-\lambda)(2-\lambda)+4(\lambda-2)+4(\lambda-2)\)
\(=(\lambda-2)\big((6-\lambda)(4-\lambda)+4+4\big)\)
Obtains correct factor of \((\lambda-2)^2\) and deduces 2 is a repeated eigenvalueA1* Must see statement about 2 being repeated; just listing 2 twice insufficient
Identifies 8 as other eigenvalueB1 B0 if not identified in (a) but full marks can be scored in (b) and (c)
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Uses correct method to find at least one eigenvectorM1
Obtains one correct eigenvector for \(\lambda=8\)A1
Obtains one correct eigenvector for \(\lambda=2\)A1
Obtains two correct linearly independent eigenvectors for \(\lambda=2\)A1 Common examples: \(\begin{pmatrix}1\\1\\-1\end{pmatrix}, \begin{pmatrix}1\\3\\1\end{pmatrix}, \begin{pmatrix}2\\5\\1\end{pmatrix}, \begin{pmatrix}1\\4\\2\end{pmatrix}\)
Part (c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Forms matrix with three different non-zero eigenvectors as columns (or normalised/scaled versions)M1
Correct matrix with eigenvectors as columns in any orderA1ft Follow through their three different vectors which are not multiples of any other
# Question 1 (Eigenvalues/Eigenvectors):

## Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Attempts to expand determinant to find characteristic polynomial | M1 | Other expansion methods possible |
| Correct expansion (need not be simplified, need not equal zero) | A1 | Allow recovery of missing brackets if indicated by later working |
| Attempts to take out factor of $(\lambda - 2)$ | M1 | May first expand to cubic or spot factor |
| $(6-\lambda)\big((3-\lambda)^2-1\big)+2\big(2(\lambda-3)+2\big)+2\big(2-2(3-\lambda)\big)=(6-\lambda)(4-\lambda)(2-\lambda)+4(\lambda-2)+4(\lambda-2)$ | | |
| $=(\lambda-2)\big((6-\lambda)(4-\lambda)+4+4\big)$ | | |
| Obtains correct factor of $(\lambda-2)^2$ and deduces 2 is a repeated eigenvalue | A1* | Must see **statement** about 2 being repeated; just listing 2 twice insufficient |
| Identifies 8 as other eigenvalue | B1 | B0 if not identified in (a) but full marks can be scored in (b) and (c) |

## Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Uses correct method to find at least one eigenvector | M1 | |
| Obtains one correct eigenvector for $\lambda=8$ | A1 | |
| Obtains one correct eigenvector for $\lambda=2$ | A1 | |
| Obtains two correct linearly independent eigenvectors for $\lambda=2$ | A1 | Common examples: $\begin{pmatrix}1\\1\\-1\end{pmatrix}, \begin{pmatrix}1\\3\\1\end{pmatrix}, \begin{pmatrix}2\\5\\1\end{pmatrix}, \begin{pmatrix}1\\4\\2\end{pmatrix}$ |

## Part (c):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Forms matrix with three **different non-zero** eigenvectors as columns (or normalised/scaled versions) | M1 | |
| Correct matrix with eigenvectors as columns in any order | A1ft | Follow through their three **different** vectors which are **not multiples** of any other |

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\begin{enumerate}
  \item A complex number $z = x + \mathrm { i } y$ is represented by the point $P$ in an Argand diagram.
\end{enumerate}

Given that

$$| z - 3 | = 4 | z + 1 |$$

(a) show that the locus of $P$ has equation

$$15 x ^ { 2 } + 15 y ^ { 2 } + 38 x + 7 = 0$$

(b) Hence find the maximum value of $| z |$

\hfill \mbox{\textit{Edexcel FP2 2019 Q1 [5]}}